8x-4
if you rearrange it, it becomes 4y + 8 = 3x2 -2x +1 4y = 3x2 -2x -7 y= (3x2 -2x -7)/4 which is a parabola
y=x2+2x+1 -b -2 2a= 2= -1 = axis of symmetry is negative one.
(2x + 1)(2x + 1) or (2x + 1)2
4x2 + 12x + 5 = 4x2 + 2x + 10x + 5 = 2x(2x+1) + 5(2x+1) = (2x+1)(2x+5)
Yes.
The [ 2x + 1 ] represents a function of 'y' .
8x-4
y = x2 + 2x + 1zeros are:0 = x2 + 2x + 10 = (x + 1)(x + 1)0 = (x + 1)2x = -1So that the graph of the function y = x + 2x + 1 touches the x-axis at x = -1.
Zero. The sum of anything and it's opposite is zero, that's how an opposite is defined. In this case, the opposite of 2x + 1 is -(2x + 1) = -2x - 1 by the distributive property. Adding like terms, 2x + -2x + 1 +-1 = 0 + 0 = 0.
4
if you rearrange it, it becomes 4y + 8 = 3x2 -2x +1 4y = 3x2 -2x -7 y= (3x2 -2x -7)/4 which is a parabola
y=x2+2x+1 -b -2 2a= 2= -1 = axis of symmetry is negative one.
(2x + 1)(2x + 1) or (2x + 1)2
x=1
x = 0
4x2 + 12x + 5 = 4x2 + 2x + 10x + 5 = 2x(2x+1) + 5(2x+1) = (2x+1)(2x+5)