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f'(x)=-3

the derivative of e is zero because its a constant. Derivative of -3x is -3. Bring the exponent of x down in front of the -3 and subtract the original exponent by 1. Ex. -3(1...which is the first exponent of the x)x^0(n-1 or 1-1=0)
all this is -3(1)x^0

x^0 is 1 so the derivative of -3x is -3

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Q: What is the derivative of e-3x?
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