d/dx e3x = 3e3x
Chat with our AI personalities
The integral of 3x is ln(3)*3x. Take the natural log of the base and multiply it by the base raised to the power.
f(x)=ln3x f1(x)=3/3x=1/x
y"+y'=0 is a differential equation and mean the first derivative plus the second derivative =0.Look at e-x the first derivative is -e-xThe second derivative will be e-xThe sum will be 0
(eu)'=ueu-1
If dy/dx = (e) (9x) then Y = 4.5ex2 plus (any constant).==================================The above answer explains how to get the integral of e9x.If you were interested in how to get the derivative of e9x, the answer is e9.I suspect you may have actually wanted to ask how to get the derivative of e9x.In that case, the derivative of e9x is 9e9x.