It depends on how wide your lengths of wood are.
Using Pythagoras' theorem it works out as 4 times the square root of 13 which is about 14.422 to 3 decimal places
Assuming that the measurements refer to a rectangle, the diagonal would be sqrt(272 + 122) = sqrt(729 + 144) = sqrt(873) = 29.55 ft (to 2 dp)
A 9 x 12 rectangle has a diagonal of 15.
Pythagoras! Diagonal = sqrt (122 + 162) = sqrt 144 + 256 = sqrt 400 = 20
A 12" x 12" square has a diagonal measurement of: 16.97 inches.
The diagonal of a 12' x 24' rectangle is approx 26.8'.
The diagonal is ~16.97 feet.
The diagonal is 20.
Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 12 × √2 ≈ 17.0 units
32.311
The diagonal is 20.
14 ft
Oh, dude, you're hitting me with the math questions now? Okay, okay, so if you wanna find the diagonal of an 8 ft by 12 ft rectangle, you can use the Pythagorean theorem. It's like a^2 + b^2 = c^2, so in this case, 8^2 + 12^2 = c^2. Just crunch those numbers and you'll get the diagonal length. Easy peasy, right?
Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13
It depends on how wide your lengths of wood are.
I assume that you refer to a 12 ft x 12 ft 8 in square. The length of the diagonal is determined easily suing Pythororas's therem: Diagonal = sqrt[122 + (128/12)2] feet = sqrt(304.4... ) ft = 17.448 ft approx.