Assuming that the measurements refer to a rectangle, the diagonal would be
sqrt(272 + 122) = sqrt(729 + 144) = sqrt(873) = 29.55 ft (to 2 dp)
By Pythagoras, (Diagonal)2 = 362 + 562 = 1296 + 3136 = 4432 sq ft So diagonal = +sqrt(4432) = 66.75 ft
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem. For a rectangle measuring 16 feet by 38 feet, the diagonal (d) can be calculated as (d = \sqrt{(16^2 + 38^2)}). This results in (d = \sqrt{(256 + 1444)} = \sqrt{1700} \approx 41.23) feet. Therefore, the diagonal measurement is approximately 41.23 feet.
divide 27 by 12 ( number of inches in a foot
Approximately 17 feet.
Using Pythagoras Theorem then the diagonal = √(242 + 242) = √1152 = 33.94 ft (2dp)
The diagonal measurement of an 8 ft square is: 11.31 feet.
14 ft
I assume that you refer to a 12 ft x 12 ft 8 in square. The length of the diagonal is determined easily suing Pythororas's therem: Diagonal = sqrt[122 + (128/12)2] feet = sqrt(304.4... ) ft = 17.448 ft approx.
The diagonal is ~16.97 feet.
To find the diagonal measurement of a square, you can use the Pythagorean theorem, which states that the square of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides. In this case, the diagonal measurement would be the square root of (7^2 + 8^2) = √(49 + 64) = √113. Therefore, the diagonal measurement of a 7 ft by 8 ft square is approximately 10.63 feet.
About 8.5 feet.
By Pythagoras, (Diagonal)2 = 362 + 562 = 1296 + 3136 = 4432 sq ft So diagonal = +sqrt(4432) = 66.75 ft
Around 17.8. I did this with cossin, but check the answer with a calculator
36.8782 ft
(Diagonal)2 = (36)2 + (26)2 = 1,972Diagonal = sqrt(1,972) = 44.4072 (rounded)
20 ft
46.648 ft