By Pythagoras, (Diagonal)2 = 362 + 562 = 1296 + 3136 = 4432 sq ft So diagonal = +sqrt(4432) = 66.75 ft
Divide by '12' 27/12 = 2 ft 3 inches or 2.25 ft.
Approximately 17 feet.
Using Pythagoras Theorem then the diagonal = √(242 + 242) = √1152 = 33.94 ft (2dp)
Sqrt(282 + 402) = a whisker under 48 ft 10 in
The diagonal measurement of an 8 ft square is: 11.31 feet.
14 ft
I assume that you refer to a 12 ft x 12 ft 8 in square. The length of the diagonal is determined easily suing Pythororas's therem: Diagonal = sqrt[122 + (128/12)2] feet = sqrt(304.4... ) ft = 17.448 ft approx.
The diagonal is ~16.97 feet.
To find the diagonal measurement of a square, you can use the Pythagorean theorem, which states that the square of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides. In this case, the diagonal measurement would be the square root of (7^2 + 8^2) = √(49 + 64) = √113. Therefore, the diagonal measurement of a 7 ft by 8 ft square is approximately 10.63 feet.
About 8.5 feet.
By Pythagoras, (Diagonal)2 = 362 + 562 = 1296 + 3136 = 4432 sq ft So diagonal = +sqrt(4432) = 66.75 ft
Around 17.8. I did this with cossin, but check the answer with a calculator
36.8782 ft
(Diagonal)2 = (36)2 + (26)2 = 1,972Diagonal = sqrt(1,972) = 44.4072 (rounded)
20 ft
Oh, dude, you're hitting me with the math questions now? Okay, okay, so if you wanna find the diagonal of an 8 ft by 12 ft rectangle, you can use the Pythagorean theorem. It's like a^2 + b^2 = c^2, so in this case, 8^2 + 12^2 = c^2. Just crunch those numbers and you'll get the diagonal length. Easy peasy, right?