Assuming that the measurements refer to a rectangle, the diagonal would be
sqrt(272 + 122) = sqrt(729 + 144) = sqrt(873) = 29.55 ft (to 2 dp)
By Pythagoras, (Diagonal)2 = 362 + 562 = 1296 + 3136 = 4432 sq ft So diagonal = +sqrt(4432) = 66.75 ft
Divide by '12' 27/12 = 2 ft 3 inches or 2.25 ft.
Approximately 17 feet.
Using Pythagoras Theorem then the diagonal = √(242 + 242) = √1152 = 33.94 ft (2dp)
Sqrt(282 + 402) = a whisker under 48 ft 10 in
The diagonal of a rectangle 8 feet by 12 feet is √208 feet, or about 14 feet 5.06 inches.
The diagonal measurement of an 8 ft square is: 11.31 feet.
14 ft
I assume that you refer to a 12 ft x 12 ft 8 in square. The length of the diagonal is determined easily suing Pythororas's therem: Diagonal = sqrt[122 + (128/12)2] feet = sqrt(304.4... ) ft = 17.448 ft approx.
The diagonal is ~16.97 feet.
Don't tell me you are in class!
About 8.5 feet.
By Pythagoras, (Diagonal)2 = 362 + 562 = 1296 + 3136 = 4432 sq ft So diagonal = +sqrt(4432) = 66.75 ft
Around 17.8. I did this with cossin, but check the answer with a calculator
36.8782 ft
(Diagonal)2 = (36)2 + (26)2 = 1,972Diagonal = sqrt(1,972) = 44.4072 (rounded)
46.648 ft