The discriminant is 16
x2+11x+121 = x+96 x2+11x-x+121-96 = 0 x2+10x+25 = 0 Discriminant = b2-4ac = 102-4*1*25 = 0 The discriminant is equal to 0 so the quadratic equation will have two equal roots. (x+5)(x+5) = 0 Therefore: x = -5 and also x = -5 the answer is 0
4
x = -28 / -11^2
It is B, 0.
The discriminant is 16
The discriminant is 0.
x2+11x+121 = x+96 x2+11x-x+121-96 = 0 x2+10x+25 = 0 Discriminant = b2-4ac = 102-4*1*25 = 0 The discriminant is equal to 0 so the quadratic equation will have two equal roots. (x+5)(x+5) = 0 Therefore: x = -5 and also x = -5 the answer is 0
21
4
x = -28 / -11^2
x^3 - 121x
x^3 - 121x
The discriminant in the quadratic equation x2 + 11x + 121 = x + 96 is 0.Simplify the equation to the form Ax2 + Bx + C = 0 and you get x2 + 10x + 25 = 0. The discriminant is B2 - 4AC or 100 - (4)(1)(25) or 100 - 100 or 0.Not asked, but answered for completeness - since the discriminant is 0, there is one real solution, namely x = (-10 +/- 00.5) / 2 = -5
It is B, 0.
x^(2)+121=x+96 Standard form of quadratic eqn.: ax^(2)+bx+c=0 Thus, x^(2)-x+25=0 Discriminant formula: We let, a= 1; b= -1; c= 25 D=b^(2)-4ac Thus, D=(-1)^2-4(1)(25) D=-99
3x2 - 11x - 4 = (x-4)(3 x + 1)