y = 6x2 + x -1 ??
discriminant = b2 - 4ac = 12 - 4(6)(-1) = 25
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If the quadratic equation:ax^2 + bx + c has discriminant dthen its roots are x1 = [-b - sqrt(d)]/2a and x2 = [-b + sqrt(d)]/2aIf d > 0 then sqrt(d) is real and non-zero. As a result x1 and x2 are real and distinct.If d = 0 then sqrt(d) = 0 and so x1 = x2 and both are real.If d < 0 the sqrt(d) is imaginary so x1 and x2 form a complex conjugate pair.
If the discriminant is negative, there are 0 interceptsIf the discriminant is zero, there is 1 interceptIf the discriminant is positive, there are 2 intercepts
The discriminant is -7
The discriminant is 16
The discriminant can be positive, zero or negative.