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What is the distance between the origin of a Cartesian coordinate system and the point 4 -6?
10
What is the distance formula between 2 6 and 5 2?
(Distance)2 = (2 - 5)2 + (6 - 2)2
What is the length of 3 0 0 -6?
Distance between (3, 0) and (0, -6) = sqrt[(3 - 0)2 + (0 - -6)2] = sqrt(32 + 62) = sqrt(45) = 3*sqrt(5) or 6.71 approx.
What is the distance between the points (22) and (8-6)?
Points: (2, 2) and (8, -6) Distance: 10
What is the distance between the origin of a Cartesian coordinate system and the point -6 7?
Using the Law of Pythagoras, you get square root of (62 + 72).The distance between the origin and the point ( -6, 7 ) is ~9.22To find the distance, we use the distance formula.c2 = a2 + b2This is an adaptation from the Pythagorean theorem. In this case, a is the difference in x coordinates; b the difference in y.The Cartesian origin is at ( 0, 0 ). So...c2 = ( -6 - 0 )2 + ( 7 - 0 )2c2 = -62 + 72c2 = 36 + 49c2 = 85c =~ 9.22
What is the distance between the orgin and point of -19 6?
Distance, by Pythagoras, = sqrt(192 + 62) = sqrt(397) = 19.9 approx.
What is the distance between the origin of a Cartesian coordinate system and the point 4 -6?
10
Find the distance between the points -2 -10 and -8 -2?
The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 (-6) and a vertical distance y2-y1 (8). The square root of the squares is sqrt [62 + 82] = sqrt [100] = 10.
What is the distance between 4 -2 and -1 6?
What is the distance between (4, -2) and (-1,6)?
What is the distance formula between 2 6 and 5 2?
(Distance)2 = (2 - 5)2 + (6 - 2)2
What is the length of 3 0 0 -6?
Distance between (3, 0) and (0, -6) = sqrt[(3 - 0)2 + (0 - -6)2] = sqrt(32 + 62) = sqrt(45) = 3*sqrt(5) or 6.71 approx.
What is the distance between points (-6 1) and (-2 -2)?
Points: (-6, 1) and (-2, -2) Distance: 5 units
What is the distance between the points (22) and (8-6)?
Points: (2, 2) and (8, -6) Distance: 10
What is the distance between points A 4 6 3 and B -2 2 -2?
Sqrt[(4+2)2 + (6-2)2 + (3+2)2] = Sqrt[62 + 42 + 52] = sqrt[36 + 16 + 25] = sqrt(77) = 8.7750 (to 4 dp)
What is the distance between the origin of a Cartesian coordinate system and the point -6 7?
Using the Law of Pythagoras, you get square root of (62 + 72).The distance between the origin and the point ( -6, 7 ) is ~9.22To find the distance, we use the distance formula.c2 = a2 + b2This is an adaptation from the Pythagorean theorem. In this case, a is the difference in x coordinates; b the difference in y.The Cartesian origin is at ( 0, 0 ). So...c2 = ( -6 - 0 )2 + ( 7 - 0 )2c2 = -62 + 72c2 = 36 + 49c2 = 85c =~ 9.22
What is the distance between the origin of a Cartesian coordinate system and the point 6 7?
Distance = sqrt(62 + 72) = sqrt(36 + 49) = sqrt(85) = 9.2195
Find the distance between (6, -2) and (1, -2)?
5
