Points: (1, -2) and (1, -5) Distance: 3 units by using the distance formula
Distance from (0, 0) to (5, 12) using distance formula is 13
The distance between two points in a plane can be found using the distance formula: sqrt((x2 - x1)^2 + (y2 - y1)^2). In this case, the distance between the points (-1, 2) and (2, 6) is sqrt((2 - (-1))^2 + (6 - 2)^2) = sqrt(3^2 + 4^2) = sqrt(9 + 16) = sqrt(25) = 5.
Points: (6, 5) and (30, 15) Distance: 26 by using the distance formula
-2 & 5
Points: (1, -2) and (1, -5) Distance: 3 units by using the distance formula
To find the distance between two points in 3D space (x1, y1, z1) and (x2, y2, z2), use the distance formula: Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2) Substitute the coordinates into the formula to find the distance.
Distance from (0, 0) to (5, 12) using distance formula is 13
If you mean points of (-2, 4) and (5, 4) then using the distance formula it is 7
The distance between two points in a plane can be found using the distance formula: sqrt((x2 - x1)^2 + (y2 - y1)^2). In this case, the distance between the points (-1, 2) and (2, 6) is sqrt((2 - (-1))^2 + (6 - 2)^2) = sqrt(3^2 + 4^2) = sqrt(9 + 16) = sqrt(25) = 5.
Points: (6, 5) and (30, 15) Distance: 26 by using the distance formula
Points: (2, 4) and (5, 0) Distance: 5
Using the distance formula it is the square root of 61 which is about 7.8 to the nearest tenth
3 because 5- 2 is 3.
-2 & 5
(2-5)2+(5-7)2 = 13 and the square root of this is the distance which is about 3.60555 to 5 decimal places
If you mean points of (-5, 1) and (-2, 3) then using the distance formula it is the square root of 13 or about 3.61 rounded to 2 decimal places