(Distance)2 = (2 - 5)2 + (6 - 2)2
To find the distance between the points (-2, 5) and (-2, 0), we can use the distance formula. Since both points have the same x-coordinate (-2), the distance is simply the difference in their y-coordinates: |5 - 0| = 5. Therefore, the distance between the two points is 5 units.
Points: (1, -2) and (1, -5) Distance: 3 units by using the distance formula
To find the distance between the points (7, 5) and (4, 9), you can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Plugging in the values, ( d = \sqrt{(4 - 7)^2 + (9 - 5)^2} = \sqrt{(-3)^2 + (4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5 ). Therefore, the distance between the two points is 5 units.
Distance from (0, 0) to (5, 12) using distance formula is 13
To find the distance between the points (-3, 2) and (5, -1), you can use the distance formula: (d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}). Substituting the coordinates, we get (d = \sqrt{(5 - (-3))^2 + (-1 - 2)^2} = \sqrt{(5 + 3)^2 + (-3)^2} = \sqrt{8^2 + (-3)^2} = \sqrt{64 + 9} = \sqrt{73}). Thus, the distance between the two points is (\sqrt{73}), which is approximately 8.54.
To find the distance between the points (-2, 5) and (-2, 0), we can use the distance formula. Since both points have the same x-coordinate (-2), the distance is simply the difference in their y-coordinates: |5 - 0| = 5. Therefore, the distance between the two points is 5 units.
Points: (1, -2) and (1, -5) Distance: 3 units by using the distance formula
To find the distance between two points in 3D space (x1, y1, z1) and (x2, y2, z2), use the distance formula: Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2) Substitute the coordinates into the formula to find the distance.
Distance from (0, 0) to (5, 12) using distance formula is 13
To find the distance between the points (7, 5) and (4, 9), you can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Plugging in the values, ( d = \sqrt{(4 - 7)^2 + (9 - 5)^2} = \sqrt{(-3)^2 + (4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5 ). Therefore, the distance between the two points is 5 units.
If you mean points of (-2, 4) and (5, 4) then using the distance formula it is 7
To find the distance between the points (-3, 2) and (5, -1), you can use the distance formula: (d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}). Substituting the coordinates, we get (d = \sqrt{(5 - (-3))^2 + (-1 - 2)^2} = \sqrt{(5 + 3)^2 + (-3)^2} = \sqrt{8^2 + (-3)^2} = \sqrt{64 + 9} = \sqrt{73}). Thus, the distance between the two points is (\sqrt{73}), which is approximately 8.54.
The distance between two points in a plane can be found using the distance formula: sqrt((x2 - x1)^2 + (y2 - y1)^2). In this case, the distance between the points (-1, 2) and (2, 6) is sqrt((2 - (-1))^2 + (6 - 2)^2) = sqrt(3^2 + 4^2) = sqrt(9 + 16) = sqrt(25) = 5.
To find the distance between the points (2, 5) and (-4, 8), you can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Plugging in the coordinates, the expression becomes: [ d = \sqrt{((-4) - 2)^2 + (8 - 5)^2} = \sqrt{(-6)^2 + (3)^2} = \sqrt{36 + 9} = \sqrt{45} ] Thus, the distance is ( \sqrt{45} ) or ( 3\sqrt{5} ).
To find the distance between the points (7, 6) and (-5, 3), you can use the distance formula: (d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}). Plugging in the values, we get (d = \sqrt{(-5 - 7)^2 + (3 - 6)^2} = \sqrt{(-12)^2 + (-3)^2} = \sqrt{144 + 9} = \sqrt{153}). The distance is approximately 12.25 units.
Points: (6, 5) and (30, 15) Distance: 26 by using the distance formula
Points: (2, 4) and (5, 0) Distance: 5