The distance is the square root of [(6--3)squared+(2--2)squared] = 9.849 rounded to 3 decimal places
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If you mean points of (6, -2) and (3, -9) then it is the square root of 58 using the distance formula
Using Pythagoras: distance = √(difference_in_x^2 + difference_in_y^2) = √((6 - 2)^2 + (3 - 4)^2) = √(16 + 1) = √17 ≈ 4.12
Points: (6, -2) and (6, 2)Using the distance formula: 4
The distance between two points in a plane can be found using the distance formula: sqrt((x2 - x1)^2 + (y2 - y1)^2). In this case, the distance between the points (-1, 2) and (2, 6) is sqrt((2 - (-1))^2 + (6 - 2)^2) = sqrt(3^2 + 4^2) = sqrt(9 + 16) = sqrt(25) = 5.
(Distance)2 = (2 - 5)2 + (6 - 2)2