5 is.
It is the square root of (-3-0)2+(-4-0)2 = 5
Distance from (0, 0) to (5, 12) using distance formula is 13
Distance = sqrt[(Y2 - Y1)2 + (X2 - X1)2]Distance = sqrt[(9 - - 3)2 + (0 - 5)2]Distance = sqrt[(12)2 + (- 5)2]Distance = sqrt(144 + 25)Distance = sqrt(169)Distance = 13 units================
Dist2 = [(5 - 0)2 + (3 - 9)2] = [52 + 62] = 25 + 36 = 61 So distance = sqrt(61) = 7.81 (approx).
1
5 is.
It is the square root of (-3-0)2+(-4-0)2 = 5
It is the square root of (-3-0)2+(-4-0)2 = 5
Points: (2, 4) and (5, 0) Distance: 5
Distance from (0, 0) to (5, 12) using distance formula is 13
Distance = sqrt[(Y2 - Y1)2 + (X2 - X1)2]Distance = sqrt[(9 - - 3)2 + (0 - 5)2]Distance = sqrt[(12)2 + (- 5)2]Distance = sqrt(144 + 25)Distance = sqrt(169)Distance = 13 units================
If that is 3.0 and -1.5 the answer is 4.5If that is 30 and -15 the answer is 45
You could write them out to show the distance on the numberline-5 -4 -3 -2 -1 0 +1 +2 +3 +4 +5or subtract minus 5 from 55 - -5 = 10
Dist2 = [(5 - 0)2 + (3 - 9)2] = [52 + 62] = 25 + 36 = 61 So distance = sqrt(61) = 7.81 (approx).
Distance between (3, 0) and (0, -6) = sqrt[(3 - 0)2 + (0 - -6)2] = sqrt(32 + 62) = sqrt(45) = 3*sqrt(5) or 6.71 approx.
Let (x1, y1) = (-2, 0) and (x2, y2) = (5, 3). Distance between two points = square root of [(x2 - x1)2 + (y2 - y1)2] = square root of [(5 - -2)2 + (3 - 0)2] = square root of (72 + 32) = square root of 58