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The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 (12) and a vertical distance y2-y1 (-16). The square root of the squares is sqrt [122 + (-16)2] = sqrt [144 + 256] = sq rt [400] = 20.

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Q: Find the distance between the points -4 15 and 8 -1?
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Find the distance between the points A 9 3 and B 15 11?

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What is the distance between (15 -17) and (-7 -17) in the coordinate?

The distance works out as 22 between the points of (15, -17) and (-7, -17)


What is the distance between the points (-7 -13) and (8 -5)?

To find the distance between two points (x0, y0) and (x1, y1) use Pythagoras: distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((8 - -7)² + (-5 - -13)²) → distance = √(15² + 8²) → distance = √289 → distance = 17 units.


Explain how to find the distance between the points (28-17) and (-15-17) on a coordinate plane?

the first point is x = 28 and y = -17. The second point is x = -15 and y = -17. Since both points have the same y coordinate then the points are on a straight horizontal line and distance is the difference of the x coordinates, or 28 - (-15) = 43


Explain how to find the distance between the points (28 -17) and (-15-17) on a coordinate plane?

To find the distance between any two points on the Cartesian plane use Pythagoras: The distance between (x0, y0) and (x1, y1) is given by: distance = √((x1 - x0)² + (y1 - y0)²) → distance between (28, -17) and (-15, -17) is: distance = √((x1 - x0)² + (y1 - y0)²) = √((-15 - 28)² + (-17 - -17)²) = √((-43)² + (0)) = √1849 = 43 ------------------------ In this case, the y-coordinates are the same (y0 = y1 = -17), so this becomes: distance = √((x1 - x0)² + (y0 - y0)²) = √((x1 - x0)² + 0²) = √((x1 - x0)²) = |x1 - x0| The vertical bars around the expression mean the absolute value of the expression, which is the numerical value of the expression ignoring the sign. distance = |x1 - x0| = |-15 - 28| = |-43| = 43.