Gradient of line = (4 - 1)/(2 + 3) = 3/5
So general form of equation: y = 3x/5 + c where c is a constant
or 5y = 3x + c' where c' = 5c is a constant
The point (2,4) is on this line
so 20 = 6 + c' so tha c' = 14
Therefore, the equation of the line is: 5y = 3x + 14
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1 Points: (1, 2) and (3, 4) 2 Slope: (2-4)/(1-3) = 1 3 Perpendicular slope: -1 4 Midpoint: (1+3)/2 and (2+4)/2 = (2, 3) 5 Equation: y-2 = 1(x-1) => y = x+1 6 Bisector equation: y-3 = -1(x-2) => y = -x+5
Points: (-1, 2) and (5, 2) Slope: 0 Equation: y = 2
Points: (-1, 6) and (2, -6) Slope: -4 Equation: y = -4x+2
It is in its general form: 2x+7y-14 = 0
Points: 0 2 and 6 0 Equation: y = -1/3x+2