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What is the equation of the line joining the points 1 1 and 7 2?
Wiki User
∙ 13y ago
Points: (1, 1) and (7, 2)
Slope: (2-1)/(7-1) = 1/6
Equation: y -1 = 1/6(x -1)
y = 1/6x -1/6+1 => y = 1/6x +5/6
Which can be expressed in the form of: x -6y +5 = 0
Wiki User
∙ 13y ago
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What is the equation in slope intercept form of the line joining the points -2.5 -0.5 and 4.5 -1?
Points: (-2.5, -0.5) and (4.5, -1) Slope: -1/14 Equation: y = -1/14x-19/28 in slope intercept form
What points are on the line given by the equation y 2x - 3?
-1
What is The graph of a line passes through the points (0 -2) and (6 0). What is the equation of the line?
Points: (0, -2) and (6, 0) Slope: 1/3 Equation of line: 3y = x-6
What is the length of line segment joining points -6 1 and 6 6?
13 units in length
How can you find equation of the line passing thruogh two points?
. the equation of a straight line can be found by using two points on a line . First find the gradient of the line using the gradient formula . now substitute the gradient into general form replacing "m" . use one of the points and substitute into equation to solve "c" example 1: find the equation of the line which passes through the points (1,3) and (2,5). step 1: find the gradient M=5-3/2-1=2 (/=divide) step 2: place m into the equation Y=2x+c step 3: substitute point into equation 3=2(1)+c step 4: solve C=1 equation is Y=2x+1 hope that helps :)
What is the equation in slope intercept form of the line joining the points -2.5 -0.5 and 4.5 -1?
Points: (-2.5, -0.5) and (4.5, -1) Slope: -1/14 Equation: y = -1/14x-19/28 in slope intercept form
The equation of the line joining through -1 3 amd parallel to the line joining 6 3 2 -3?
To find the equation of a line parallel to another line, we need the same direction vector. The direction vector of the given line is (2, -3). Therefore, the equation of the line parallel to it passing through (-1, 3) is x = -1 + 2t and y = 3 - 3t, where t is a parameter.
What equation of the line that contains the point 1 -1 and 2 -2?
Choose the equation of the line that contains the points (1, -1) and (2, -2).
What points are on the line given by the equation y 2x - 3?
-1
What is the equation of the line that passes through 1 5 and 4 11?
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
What are the points that lie on the line 3x-y2?
1
Which is not an equation of the line that passes through the points 1 1 and 5 5?
The equation for the given points is y = x+4 in slope intercept form
What is the equation of the line passing through the points 2 2 and 3 1?
Points: (2, 2) and (3, 1) Slope: -1 Equation: y = -x+4
What is the equation of the straight line from the origin to the midpoint of the line joining 3 2 and 5 -1?
It will have no y intercept and it is: y = 0.125x
What is the midpoint of the line joining the points (3, 2) and (1, 4)?
The midpoint is (2,3)
What is an equation of the locus of points equidistant from the points 4 1 and 10 1?
Every point equidistant from (4, 1) and (10, 1) lies on the line [ x = 7 ],and that's the equation.
What is the equation of the line containing the points (3 1) (9 3) and (27 9)?
The straight line equation works out as: 3y = x
