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If you mean points of: (2, -8) and (0, 0) then the slope is -4 and equation is y = -4x
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Is (x-2)(x 4)0 a quadratic equation?
If you mean: (x-2)(x+4) = 0 then it is a quadratic equation whose solutions are x = 2 or x = -4
Which equation of the line written in slope-intercept form contains the points 8 0 and 0 2?
The equation is (y - 0) = (0 - 2)/(8 - 0)*(x - 8) That is y = (-1/4)*(x - 8) = -x/4 + 2
What is the equation of the line that contains 4 -4 and -2 0?
y=-2/3x-4/3
What is the set of solutions to the equation x2-4 equals 0?
x = 2 or -2
What is the perpendicular bisector equation of the line whose coordinates are -4 8 and 0 -2 on the Cartesian plane showing work?
Points: (-4, 8) and (0, -2) Slope: (8--2)/((-4-0) = -5/2 Perpendicular slope: 2/5 Midpoint: (-4+0)/2, (8-2)/2 = (-2, 3) Equation: y-3 = 2/5(x--2) Multiply all terms by 5: 5y-15 = 2(x--2) => 5y = 2x+19 Perpendicular bisector equation in its general form: 2x-5y+19 = 0
Is (x-2)(x 4)0 a quadratic equation?
If you mean: (x-2)(x+4) = 0 then it is a quadratic equation whose solutions are x = 2 or x = -4
Choose the equation of the line that contains the points 4 -4 and -2 0?
Points: (4, -4) and (-2, 0) Slope: -2/3 Equation: y = -2/3x-4/3 or as 3y = -2x-4
What is the equation and its perpendicular bisector equation of the line spanning the points of 3 4 and 0 0 on the Cartesian plane showing work?
Points: (3, 4) and (0, 0)Slope: (4-0)/(3-0) = 4/3Equation: y-4 = 4/3(x-3) => 3y = 4xPerpendicular slope: -3/4Midpoint: (3+0)/2 and (4+0)/2 = (1.5, 2)Bisector equation: y-2 = -3/4(x-1.5) => 4y = -3x+12.5
What is the equation through the line passing points 0 4 and -2 -2 on a graph?
Gradient = (4 + 2)/(0 + 2) = 6/2 = 3 So the equation is (y + 2) = 3(x + 2) or y = 3x + 4
Which equation of the line written in slope-intercept form contains the points 8 0 and 0 2?
The equation is (y - 0) = (0 - 2)/(8 - 0)*(x - 8) That is y = (-1/4)*(x - 8) = -x/4 + 2
What is the equation of a line in slope-intercept form for a line with slope 4 and y-intercept at (0 2)?
If you mean a slope of 4 and points of (0, 2) then the equation is y = 4x+2.
What is the equation of the line that contains 4 -4 and -2 0?
y=-2/3x-4/3
What is the equation of a line with points and 2-8 00?
If you mean points of: (2, -8) and (0, 0) then the slope is -4 and equation is y = -4x
What is the equation of 0 2 and 2 5?
The equation of the line through (0,2) and (2, 5) is (y - 2) = (5 - 2)/(2 - 0)*(x - 0) or 2*(y - 2) = 3*x or 3x - 2y + 4 = 0
What is the slope-intercept equation of the line that contains the points (1 2) and (0 -2)?
Points: (1, 2) and (0, -2) Slope: 4 Equation: y = 4x-2
What is the equation of a line in slope-intercept form for a line with slope 4 and y-intercept at 0 2?
If you mean a slope of 4 and points of (0, 2) then the equation is y = 4x+2.
What is the equation for (-31) and (00)?
Points: (8, 2) and (0, 0) Slope: 1/4 or 0.25 Equation: y = 0.25x
