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If you mean points of: (2, -8) and (0, 0) then the slope is -4 and equation is y = -4x
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Earn +20 ptsQ: What is the equation of (0 2) (2 0) (4 2)?
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Is (x-2)(x 4)0 a quadratic equation?
If you mean: (x-2)(x+4) = 0 then it is a quadratic equation whose solutions are x = 2 or x = -4
Which equation of the line written in slope-intercept form contains the points 8 0 and 0 2?
The equation is (y - 0) = (0 - 2)/(8 - 0)*(x - 8) That is y = (-1/4)*(x - 8) = -x/4 + 2
What is the equation of the line that contains 4 -4 and -2 0?
y=-2/3x-4/3
What is the set of solutions to the equation x2-4 equals 0?
x = 2 or -2
What is the perpendicular bisector equation of the line whose coordinates are -4 8 and 0 -2 on the Cartesian plane showing work?
Points: (-4, 8) and (0, -2) Slope: (8--2)/((-4-0) = -5/2 Perpendicular slope: 2/5 Midpoint: (-4+0)/2, (8-2)/2 = (-2, 3) Equation: y-3 = 2/5(x--2) Multiply all terms by 5: 5y-15 = 2(x--2) => 5y = 2x+19 Perpendicular bisector equation in its general form: 2x-5y+19 = 0
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