The equation of a circle centered in the origin, with radius 6, is x2 + y2 = 62. To move the coordinates of the center from (0,0) to (4,7), you change each x by (x-4), and each y by (y-7); thus, you obtain: (x-4)2 + (y-7)2 = 62.
x² + y² = 4.
This makes no sence
It is x2 + y2 = 4
I think it is center: (-4, 3) ; radius: 2 Apex:)
center 5,-3 radius 4
x² + y² = 4.
This makes no sence
It is x2 + y2 = 4
I think it is center: (-4, 3) ; radius: 2 Apex:)
Centre of the circle: (3, 8) Radius of the circle: 2 Cartesian equation of the circle: (x-3)^2 + (y-8)^2 = 4
center 5,-3 radius 4
x2 + y2 = 2
If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4
If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4
It is (x - 7)^2 + (y - 4)^2 = 4
(x+4)2 + (y-2)2 = 9 it is a circle
(x-2)2+(y-4)2=36