For a line of slope m, the equation is of the form
y= mx + c where c is the y-intercept
So for the slope indicated, the line would be Y= 6x +5.
To write the point-slope equation of a line that passes through the point (5, 5), you need a slope (m) as well. The point-slope form is given by the equation ( y - y_1 = m(x - x_1) ). If the slope is not provided, you can express the equation generically as ( y - 5 = m(x - 5) ), where ( m ) is the slope of the line. If you have a specific slope, you can substitute it into the equation.
5
The straight line equation would depend on the slope which has not been given.
The point-slope form of a line's equation is given by (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is a point on the line. Given the slope (m = -5) and the point ((1, -1)), the equation in point-slope form is (y + 1 = -5(x - 1)).
The slope is -0.2
-1
As for example in the straight line equation of y=3x+5 the slope is 3 and the y intercept is 5
5
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
The equation of the line is: y = -x-5
The straight line equation would depend on the slope which has not been given.
the slope of a line is 9/5 the y intercept is -4, express the equation of the line in point slope form
The slope of the graph of that equation is -1.
12
If the slope is 7 and the coordinate is (8, 5) then the straight line equation is y=7x-51
The slope is -0.2
8