There are an infinity of lines passing through the point whose coordinates are (2,2), each with a different slope [gradient]. The equation of the line will be of the form (y - 2) = m*(x - 2) where m is the gradient.
-3
It is the equation of a straight line in the form of: y = 2x+4
7
Rearranging the original equation, we get y=-(2/3)x+12. Since 12 is the constant, this is the point that the line of this equation will cut the y-axis if x=0. Therefore, -(2/3) is the gradient and for an equation to produce a parallel line, the gradient must be equal. Summing up, y=-(2/3)+c (where c equals any real number) would be parallel
1
There are an infinity of lines passing through the point whose coordinates are (2,2), each with a different slope [gradient]. The equation of the line will be of the form (y - 2) = m*(x - 2) where m is the gradient.
An equation such as y = mx + c is said to be in standard form. From such an equation, Gradient = coefficient of x = 3
y = 2x + 3
-3
The gradient of the given line is 2/3. Gradient of the perpendicular is -3/2 The equation, therefore, is y = -(3/2)x + 5 or 2y = -3x + 10 or 3x + 2y - 10 = 0
It is the equation of a straight line in the form of: y = 2x+4
. the equation of a straight line can be found by using two points on a line . First find the gradient of the line using the gradient formula . now substitute the gradient into general form replacing "m" . use one of the points and substitute into equation to solve "c" example 1: find the equation of the line which passes through the points (1,3) and (2,5). step 1: find the gradient M=5-3/2-1=2 (/=divide) step 2: place m into the equation Y=2x+c step 3: substitute point into equation 3=2(1)+c step 4: solve C=1 equation is Y=2x+1 hope that helps :)
7
y = 4x + 2 It has a slope (gradient) or 4. The slope/gradient of a linear function is simply the number in front of the x when the equation is in the form y=mx+b. (the coefficient of x).
y=mx+cThe equation of the line is y = mx + c wherem is the gradient of the line and c is the y-interceptThat is, y = 2x + c where c is a constant to be determined.Since the point (3, 2) is on the line,2 = 6 + c so that c = -4So the line is y = 2x - 4
Rearranging the original equation, we get y=-(2/3)x+12. Since 12 is the constant, this is the point that the line of this equation will cut the y-axis if x=0. Therefore, -(2/3) is the gradient and for an equation to produce a parallel line, the gradient must be equal. Summing up, y=-(2/3)+c (where c equals any real number) would be parallel