Y=2x+c where c is arbitery constant
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There are an infinity of lines passing through the point whose coordinates are (2,2), each with a different slope [gradient]. The equation of the line will be of the form (y - 2) = m*(x - 2) where m is the gradient.
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It is the equation of a straight line in the form of: y = 2x+4
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Rearranging the original equation, we get y=-(2/3)x+12. Since 12 is the constant, this is the point that the line of this equation will cut the y-axis if x=0. Therefore, -(2/3) is the gradient and for an equation to produce a parallel line, the gradient must be equal. Summing up, y=-(2/3)+c (where c equals any real number) would be parallel