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y = ax^2 + c where a and c are constants and a is not 0.
Yes, it does.
First the formula is g(x)=ax2+bx+c First find where the parabola cuts the x axis Then find the equation of the axis of symmetry Then
Once you calculate the X coordinate using the axis of symmetry (X=-b/2a), you plug that value in for all of the X's in the equation of the parabola. You then solve the equation for the value of Y.
the axis of symmetry
Did you mean a parabola with equation y=3x^2? The line of symmetry is x=0 or the y-axis.
Its extremum is on its axis of symmetry.
How about y = (x - 2)2 = x2 - 4x + 4 ? That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2. Its vertex is located at the point (2, 0).
x=-b/2a [negative B over 2A]
Line of symmetry: x = 3
y = ax^2 + c where a and c are constants and a is not 0.
Yes, it does.
The line of symmetry located on a parabola is right down the center. A parabola is a U shape. Depending on the direction of the parabola it either has a x axis of symmetry or y axis of symmetry. You should have two equal sides of the parabola.
First the formula is g(x)=ax2+bx+c First find where the parabola cuts the x axis Then find the equation of the axis of symmetry Then
Parallel to the y-axis, going through the highest/lowest point of the parabola (if the parabola is negative/positive, respectively).
The axis of symmetry is x = -2.
Once you calculate the X coordinate using the axis of symmetry (X=-b/2a), you plug that value in for all of the X's in the equation of the parabola. You then solve the equation for the value of Y.