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Q: What is the equation of the axis of symmetry of this parabola x(y-2)2-8?
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Related questions

What is the line of symmetry for the parabola whose equation is y -x2 x 3?

Did you mean a parabola with equation y=3x^2? The line of symmetry is x=0 or the y-axis.


Which point of parabola is on the axis of symmetry?

Its extremum is on its axis of symmetry.


An equation of a parabola that has x equals 2 as its axis of symmetry is?

How about y = (x - 2)2 = x2 - 4x + 4 ? That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2. Its vertex is located at the point (2, 0).


What is the equation for the axis of symmetry of a parabola?

x=-b/2a [negative B over 2A]


What is an equation of the axis of symmetry of the parabola represented by y equals -x2 plus 6x-4?

Line of symmetry: x = 3


Equation of parabola that has y as axis of symmetry?

y = ax^2 + c where a and c are constants and a is not 0.


A parabola has an axis of symmetry.?

Yes, it does.


Where is the line of symmety located on a parabola?

The line of symmetry located on a parabola is right down the center. A parabola is a U shape. Depending on the direction of the parabola it either has a x axis of symmetry or y axis of symmetry. You should have two equal sides of the parabola.


How do you find the gradient of a quadratic equation?

First the formula is g(x)=ax2+bx+c First find where the parabola cuts the x axis Then find the equation of the axis of symmetry Then


Where is the axis of symmetry of a parabola located?

Parallel to the y-axis, going through the highest/lowest point of the parabola (if the parabola is negative/positive, respectively).


What is the axis of symmetry for the parabola with vertex (-2 -4) and directrix y 1?

The axis of symmetry is x = -2.


How do you find the y-coordinate vertex of a parabola?

Once you calculate the X coordinate using the axis of symmetry (X=-b/2a), you plug that value in for all of the X's in the equation of the parabola. You then solve the equation for the value of Y.