(3z + 5)(z -7)
When the expression is broken down into its prime factors it is factored completely.
If you mean: y2+5y+6 then it is (y+2)(y+3) when factored completely
It is (x+6)(x-4) when factored
To completely factor the expression (48x^2 - 96), first factor out the greatest common factor, which is 48: [ 48(x^2 - 2). ] Next, the expression (x^2 - 2) can be recognized as a difference of squares, which can be factored further as: [ 48(x - \sqrt{2})(x + \sqrt{2}). ] Thus, the completely factored form of the expression is (48(x - \sqrt{2})(x + \sqrt{2})).
To factor the expression (4 + 16x + 28y), we first observe that the coefficients 4, 16, and 28 have a common factor of 4. Factoring out 4 gives us: [ 4(1 + 4x + 7y) ] Thus, the completely factored form of the expression is (4(1 + 4x + 7y)).
When the expression is broken down into its prime factors it is factored completely.
If you mean: y2+5y+6 then it is (y+2)(y+3) when factored completely
This expression can not be factored. It is already in it's simplest state.
It is (x+6)(x-4) when factored
If you mean 5x^2 -125 then it is 5(x^2 -25) when factored
27-y3 factored completely = 24
To completely factor the expression (48x^2 - 96), first factor out the greatest common factor, which is 48: [ 48(x^2 - 2). ] Next, the expression (x^2 - 2) can be recognized as a difference of squares, which can be factored further as: [ 48(x - \sqrt{2})(x + \sqrt{2}). ] Thus, the completely factored form of the expression is (48(x - \sqrt{2})(x + \sqrt{2})).
To factor the expression (4 + 16x + 28y), we first observe that the coefficients 4, 16, and 28 have a common factor of 4. Factoring out 4 gives us: [ 4(1 + 4x + 7y) ] Thus, the completely factored form of the expression is (4(1 + 4x + 7y)).
If an expression does not have a common factor, then it is called a "prime" expression.
45
It is irreducible, it can't be factored.
a3-4a = a(a2-4) when factored