It depends on what the 7' and 10' refers to. They could be adjacent sides of a rectangle or a parallelogram. If the latter, more information is required before the question can be answered.
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The diagonal of a rectangle with sides measuring 7 feet and 10 feet can be calculated using the Pythagorean theorem. The square of the diagonal is equal to the sum of the squares of the two sides, so in this case, the diagonal would be √(7^2 + 10^2) = √(49 + 100) = √149 = approximately 12.21 feet.
Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 10 cm × √2 ≈ 14.1 cm
14 The ratio of the side of a square to the diagonal is 1.4.
A diagonal line of a polygon is a line that joins any two vertices not already joined by a side. A polygon with n sides has n(n-3)/2 diagonals → a decagon has 10(10-3)/2 = 10 × 7 ÷ 2 = 35 diagonals
63
Good old Arthur. There is a Pythagorean triple (5-12-13) lurking in this question. Diagonal is 26 cm making x = 7