5
8
There are infinitely many possible rules that can be used to generate the 7 number sequence given in the question.One such is Un = (4n6 - 102n5 + 1015n4 - 4980n3 + 12511n2 - 14928n + 6720)/60 for n = 1 , 2, 3, ...There are infinitely many possible rules that can be used to generate the 7 number sequence given in the question.One such is Un = (4n6 - 102n5 + 1015n4 - 4980n3 + 12511n2 - 14928n + 6720)/60 for n = 1 , 2, 3, ...There are infinitely many possible rules that can be used to generate the 7 number sequence given in the question.One such is Un = (4n6 - 102n5 + 1015n4 - 4980n3 + 12511n2 - 14928n + 6720)/60 for n = 1 , 2, 3, ...There are infinitely many possible rules that can be used to generate the 7 number sequence given in the question.One such is Un = (4n6 - 102n5 + 1015n4 - 4980n3 + 12511n2 - 14928n + 6720)/60 for n = 1 , 2, 3, ...
5, 7, 9, 11 and 13
5/12 is in its lowest terms.
"4n6" is a common abbreviation for "forensics," typically used in the context of digital forensics or forensic science. It represents the combination of the four letters in "forensics" (4) and the two letters in "n" and "6".
+4n6!n4 +0 ..
5
it is 8.
The first five positive integer terms for 3n + 4 are: 1 = 7 2 = 10 3 = 13 4 = 16 5 = 19
2
5 first terms in n²+3
5
20, 15, 10, 5, 0, -5, -10, -15, -20 and so on.
To find the first 5 terms, plug 1, 2, 3, 4 and 5 in for n:3*1-3 = 03*2-3 = 33*3-3 = 63*4-3 = 93*5-3 = 12The first five terms are 0, 3, 6, 9 and 12.
5, 11, 17, 23, 29
4,8,12,16,20