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They are -2, 2, 6, 10 and 14.

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WHAT ARE THE FIRST THREE OF AN ARITHMETIC SEQUENCE WHOSE LAST TERM IS IF THE COMMON DIFFERENCE IS -5?

To find the first three terms of an arithmetic sequence with a common difference of -5, we first need the last term. If we denote the last term as ( L ), the terms can be expressed as ( L + 10 ), ( L + 5 ), and ( L ) for the first three terms, since each term is derived by adding the common difference (-5) to the previous term. Thus, the first three terms would be ( L + 10 ), ( L + 5 ), and ( L ).


What is 12r 5 3r -5?

To simplify the expression (12r + 5 + 3r - 5), combine like terms. First, combine the (r) terms: (12r + 3r = 15r). Then, combine the constant terms: (5 - 5 = 0). Thus, the simplified expression is (15r).


What are the first 3 terms of n-2 divided by n squared?

5


What is the first 5 terms of -3n?

8


What is the sequence for the series of numbers 4 5 7 4 8 13 7?

There are infinitely many possible rules that can be used to generate the 7 number sequence given in the question.One such is Un = (4n6 - 102n5 + 1015n4 - 4980n3 + 12511n2 - 14928n + 6720)/60 for n = 1 , 2, 3, ...There are infinitely many possible rules that can be used to generate the 7 number sequence given in the question.One such is Un = (4n6 - 102n5 + 1015n4 - 4980n3 + 12511n2 - 14928n + 6720)/60 for n = 1 , 2, 3, ...There are infinitely many possible rules that can be used to generate the 7 number sequence given in the question.One such is Un = (4n6 - 102n5 + 1015n4 - 4980n3 + 12511n2 - 14928n + 6720)/60 for n = 1 , 2, 3, ...There are infinitely many possible rules that can be used to generate the 7 number sequence given in the question.One such is Un = (4n6 - 102n5 + 1015n4 - 4980n3 + 12511n2 - 14928n + 6720)/60 for n = 1 , 2, 3, ...