The inequality of -2 and 3 can be expressed as -2 < 3. This indicates that -2 is less than 3 on the number line. In terms of a range, any number greater than -2 and less than 3 can be represented as -2 < x < 3, where x represents any value within that interval.
To solve the inequality ( x^2 < 9 ), we first rewrite it as ( x^2 - 9 < 0 ), which factors to ( (x - 3)(x + 3) < 0 ). The critical points are ( x = -3 ) and ( x = 3 ). Analyzing the intervals, we find that the solution to the inequality is ( -3 < x < 3 ). Therefore, the values of ( x ) that satisfy the inequality are those in the open interval ( (-3, 3) ).
Yes, It is a solution (a+)
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
The inequality ( x^3 < 3 ) can be solved by finding the integer values of ( x ) that satisfy this condition. To do this, we first note that ( x^3 = 3 ) has a real solution at ( x = \sqrt[3]{3} \approx 1.442 ). The integer solutions for the inequality ( x^3 < 3 ) are thus ( x = -2, -1, 0, 1 ). Therefore, the integer solutions are ( x \in {-2, -1, 0, 1} ).
The inequality you provided seems to be missing an operator (like <, >, ≤, or ≥) between 5x and 13y. Assuming you meant to write an inequality such as 5x < 13y, one possible ordered pair that satisfies this inequality is (3, 2), since 5(3) = 15 and 13(2) = 26, and 15 < 26. If you meant a different inequality, please specify, and I can provide a corresponding solution.
The above is not an inequality as stated.
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
To solve the inequality ( x^2 < 9 ), we first rewrite it as ( x^2 - 9 < 0 ), which factors to ( (x - 3)(x + 3) < 0 ). The critical points are ( x = -3 ) and ( x = 3 ). Analyzing the intervals, we find that the solution to the inequality is ( -3 < x < 3 ). Therefore, the values of ( x ) that satisfy the inequality are those in the open interval ( (-3, 3) ).
2 is a solution of the equation, but not if it's an inequality.
Yes, It is a solution (a+)
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
The inequality sign changes direction. So 2<3 Multiply by -2 and you get -4>-6 (similarly with division).
If 7 > 3x - 2 then x < 3.
x < 2/3
The inequality ( x^3 < 3 ) can be solved by finding the integer values of ( x ) that satisfy this condition. To do this, we first note that ( x^3 = 3 ) has a real solution at ( x = \sqrt[3]{3} \approx 1.442 ). The integer solutions for the inequality ( x^3 < 3 ) are thus ( x = -2, -1, 0, 1 ). Therefore, the integer solutions are ( x \in {-2, -1, 0, 1} ).
The inequality you provided seems to be missing an operator (like <, >, ≤, or ≥) between 5x and 13y. Assuming you meant to write an inequality such as 5x < 13y, one possible ordered pair that satisfies this inequality is (3, 2), since 5(3) = 15 and 13(2) = 26, and 15 < 26. If you meant a different inequality, please specify, and I can provide a corresponding solution.
x - 3 is not an inequality.