The inequality of -2 and 3 can be expressed as -2 < 3. This indicates that -2 is less than 3 on the number line. In terms of a range, any number greater than -2 and less than 3 can be represented as -2 < x < 3, where x represents any value within that interval.
To solve the inequality ( x^2 < 9 ), we first rewrite it as ( x^2 - 9 < 0 ), which factors to ( (x - 3)(x + 3) < 0 ). The critical points are ( x = -3 ) and ( x = 3 ). Analyzing the intervals, we find that the solution to the inequality is ( -3 < x < 3 ). Therefore, the values of ( x ) that satisfy the inequality are those in the open interval ( (-3, 3) ).
Yes, It is a solution (a+)
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
The inequality ( x^3 < 3 ) can be solved by finding the integer values of ( x ) that satisfy this condition. To do this, we first note that ( x^3 = 3 ) has a real solution at ( x = \sqrt[3]{3} \approx 1.442 ). The integer solutions for the inequality ( x^3 < 3 ) are thus ( x = -2, -1, 0, 1 ). Therefore, the integer solutions are ( x \in {-2, -1, 0, 1} ).
To graph the inequality ( y + 2 > -3(x + 1) ), first, rearrange it to isolate ( y ): ( y > -3x - 3 - 2 ), which simplifies to ( y > -3x - 5 ). This represents a straight line with a slope of -3 and a y-intercept of -5. Since the inequality is strict (greater than), you would draw a dashed line for ( y = -3x - 5 ) and shade the region above the line to indicate all the points that satisfy the inequality.
The above is not an inequality as stated.
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
To solve the inequality ( x^2 < 9 ), we first rewrite it as ( x^2 - 9 < 0 ), which factors to ( (x - 3)(x + 3) < 0 ). The critical points are ( x = -3 ) and ( x = 3 ). Analyzing the intervals, we find that the solution to the inequality is ( -3 < x < 3 ). Therefore, the values of ( x ) that satisfy the inequality are those in the open interval ( (-3, 3) ).
2 is a solution of the equation, but not if it's an inequality.
Yes, It is a solution (a+)
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
The inequality sign changes direction. So 2<3 Multiply by -2 and you get -4>-6 (similarly with division).
If 7 > 3x - 2 then x < 3.
x < 2/3
The inequality ( x^3 < 3 ) can be solved by finding the integer values of ( x ) that satisfy this condition. To do this, we first note that ( x^3 = 3 ) has a real solution at ( x = \sqrt[3]{3} \approx 1.442 ). The integer solutions for the inequality ( x^3 < 3 ) are thus ( x = -2, -1, 0, 1 ). Therefore, the integer solutions are ( x \in {-2, -1, 0, 1} ).
x - 3 is not an inequality.
To determine which values from the set {1, 2, 3, 4, 5} make the inequality n < 26 true, we need to find all numbers in the set that are less than 26. In this case, the values that satisfy the inequality are 1, 2, 3, 4, and 5. Therefore, the values from the set {1, 2, 3, 4, 5} that make the inequality n < 26 true are 1, 2, 3, 4, and 5.