(Diagonal)2 = (15)2 + (8)2 = (225) + (64) = 289Diagonal = sqrt(289) = 17
A 9 x 12 rectangle has a diagonal of 15.
120 feet
length of diagonal of 20 of a 20 feet and 15 width.
Diagonal = 17 cm and height = 8 cm so Length = sqrt[172 - 82] = sqrt(225) = 15 cm Then area = length*height = 15*8 = 120 cm2
The length of a rectangle that has a diagonal of 25 feet and a width of 15 feet is 20 feet.
15 cm for the diagonal.
(Diagonal)2 = (15)2 + (8)2 = (225) + (64) = 289Diagonal = sqrt(289) = 17
Use Pythagoras: diagonal² = length² + width² → diagonal² = (10 cm)² + (15 cm)² → diagonal = √(10² + 15²) cm = √325 cm = 5 √13 cm ≈ 18 cm
The length is 20 cm.
A 9 x 12 rectangle has a diagonal of 15.
15 inches (solved with the help of Pythagoras' theorem)
15 cm Solved through Pythagoras' theorem.
120 feet
length of diagonal of 20 of a 20 feet and 15 width.
Diagonal = 17 cm and height = 8 cm so Length = sqrt[172 - 82] = sqrt(225) = 15 cm Then area = length*height = 15*8 = 120 cm2
The length of the diagonal which is to opposite of 100⁰ angle is: diagonal length = √[152 + 82 - 2(15)(8)cos 100⁰] diagonal length ≈ 18 The length of the diagonal which is to opposite of 100⁰ angle is: diagonal length =√[152 + 82 - 2(15)(8)cos 80⁰] diagonal length ≈ 16