Q: What is the measure of A B C?

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If we are talking about a triangle here, then: A = 61º B = 45º C = 74º But, since you did not specify, there is an infinite number of answers.

Yes, but you would need to know a degree measure too. [Sin(A)/a] = [Sin(B)/b] = [Sin(C)/c] [a/Sin(A)] = [b/Sin(B)] = [c/Sin(C)]

In a parallelogram adjacent angles are supplementary, so angles are 75 degrees (A & C) and 105 degrees (B & D).

The answer is 4! (4 factorial), the same as 4x3x2x1, which equals 24 combinations. The answer is 24 and this is how: A b c d A b d c A c d b A c b d A d c b A d b c B c d a B c a d B d a c B d c a B a c d B a d c C d a b C d b a C a b d C a d b C b d a C b a d D a b c D a c b D b c a D b a c D c a b D c b a

b+b+b+c+c+c+c =3b+4c

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The Law of sines: a/sin A = b/sin B = c/sin CIf the angle C in the triangle ABC is 90 degrees, then the triangle ABC is a right triangle, where c is the measure of the hypotenuse, a is the measure of the leg opposite the angle A, and b is the measure of the leg opposite the angle B.Let us observe what happens when sin C = sin 90 degrees = 1.c/sin C = a/sin A cross multiply;c sin A = a sin C divide by c both sides;(c sin A)/c = (a sin C)/c simplify c on the left hand side;sin A = (a sin C)/c = [(a)(1)]/c = a/csin A = (measure of leg opposite the angle A)/(measure of hypotenuse)From the Law of Cosine we know that cos A= (b^2 + c^2 - a^2)/(2bc). If we substitute a^2 + b^2 for c^2, we have:cos A = (b^2 + (a^2+ b^2) - a^2 )/(2ab)cos A = 2b^2 /2ab simplify;cos A = b/c = (measure of leg adjacent the angle A)/(measure of hypotenuse) Therefore tan A = sin A/cos A =(a/c)/(b/c) = (a/c)(c/b) = a/b = (measure of leg opposite the angle A)/(measure of leg adjacent to angle A). And cot A = cos A/sin A = (b/c)/(a/c) = (b/c)(c/a) = b/a = (measure of leg adjacent to angle A)/(measure of leg opposite the angle A).

A = 60 B = 20 C = 140 This can have a large number of answers.

In a parallelogram adjacent angles are supplementary, so angles are 75 degrees (A & C) and 105 degrees (B & D).

how to find the measure of angle C in the following triangle

b

If we are talking about a triangle here, then: A = 61º B = 45º C = 74º But, since you did not specify, there is an infinite number of answers.

Let first angle be "A", second angle "B" and third angle "C", then C = B - 5 A = 3B + 5 But "A" + "B" + "C" must rqual 180 Substitue for "A" and "C" and we get 3B + 5 + B + B - 5 = 180 5B = 180 or B = 36 degrees Therefore A = 3 x 36 + 5 = 113 degrees and C = 31 degrees Verification: A + B + C = 113 + 36 + 31 = 180

the answer is 68 degrees

Yes, but you would need to know a degree measure too. [Sin(A)/a] = [Sin(B)/b] = [Sin(C)/c] [a/Sin(A)] = [b/Sin(B)] = [c/Sin(C)]

In a parallelogram adjacent angles are supplementary, so angles are 75 degrees (A & C) and 105 degrees (B & D).

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x=? 2x = A 4x = B 2A = B 6x = C C= 3A. or C = 1.5*B For a digit, you need to give the measurement of either A or B