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Nth term for 11 ,31,51,72?
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
What are the first 5 numbers in a sequence if the nth term is 6n plus 1?
When n = 1, sequence term (call it y) = 7. Each unit increase in n results in an increase of 6 in y, so when n = 5, y = 31. Sequence is therefore 7, 13, 19, 25, 31 etc.
What is the nth term for 23 15 7 -1 -9?
Assuming this is a linear or arithmetic sequence, the nth term is Un = 31 - 8n. But, there are infinitely many polynomials of order 5 or higher, and many other functions that will fit the above 5 numbers.
What is the nth term for 4 10 17 24 31?
There are very many possible solutions. The simplest polynomial solution is t(n) = (n^4 - 14n^3 + 71n^2 + 14n + 24)/24.
What is the nth term for 1 7 13 31 49?
There are infinitely many possible answers. the simplest polynomial is Un = -n4 + 12n3 - 47n2 + 78n - 41
