1 4 9 is a series of squared numbers.
The nth term is [ n squared ]
The sequence 5, 9, 13, 17 is an arithmetic sequence where each term increases by 4. The first term (a) is 5, and the common difference (d) is 4. The nth term can be expressed using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is given by ( a_n = 5 + (n-1) \cdot 4 = 4n + 1 ).
tn = n2
To find the nth term of the linear sequence -9, -5, -1, we first identify the common difference between the terms. The difference between consecutive terms is 4. The first term (a) is -9, so the nth term can be expressed as ( a_n = -9 + (n-1) \cdot 4 ), which simplifies to ( a_n = 4n - 13 ).
The sequence 1, 5, 9, 13 is an arithmetic sequence where the first term is 1 and the common difference is 4. The nth term can be found using the formula: ( a_n = a_1 + (n-1) \cdot d ), where ( a_1 ) is the first term and ( d ) is the common difference. Substituting the values, we get ( a_n = 1 + (n-1) \cdot 4 ). Simplifying this, the nth term is ( a_n = 4n - 3 ).
The given sequence is an arithmetic sequence where each term increases by 4. The first term (a) is 13, and the common difference (d) is 4. The nth term can be found using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 13 + (n-1) \cdot 4 = 4n + 9 ).
The nth term is n2.
7n+4
n2
This is an Arithmetic Series/Sequence. In general the nth term, A(n) = a + (n - 1)d....where a is the 1st term and d is the common difference. In this question, the 1st term equals 1 and the common difference is 4. Then the nth term, A(n) = 1 + (n - 1) x 4 = 1 + 4n - 4 = 4n - 3.
The sequence 5, 9, 13, 17 is an arithmetic sequence where each term increases by 4. The first term (a) is 5, and the common difference (d) is 4. The nth term can be expressed using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is given by ( a_n = 5 + (n-1) \cdot 4 = 4n + 1 ).
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
tn = n2
To find the nth term of the linear sequence -9, -5, -1, we first identify the common difference between the terms. The difference between consecutive terms is 4. The first term (a) is -9, so the nth term can be expressed as ( a_n = -9 + (n-1) \cdot 4 ), which simplifies to ( a_n = 4n - 13 ).
The sequence 1, 5, 9, 13 is an arithmetic sequence where the first term is 1 and the common difference is 4. The nth term can be found using the formula: ( a_n = a_1 + (n-1) \cdot d ), where ( a_1 ) is the first term and ( d ) is the common difference. Substituting the values, we get ( a_n = 1 + (n-1) \cdot 4 ). Simplifying this, the nth term is ( a_n = 4n - 3 ).
4 Four Qutro The correct answer is: The nth term is 4n + 1
The nth term of the sequence is 2n + 1.
The given sequence is an arithmetic sequence where each term increases by 4. The first term (a) is 13, and the common difference (d) is 4. The nth term can be found using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 13 + (n-1) \cdot 4 = 4n + 9 ).