tn = n2
The given sequence is decreasing by 1 each time, starting from 9. Therefore, the nth term of this sequence can be represented by the formula ( a_n = 10 - n ), where ( a_n ) is the nth term and n represents the position in the sequence.
7 - 4n where n denotes the nth term and n starting with 0
It is increasing by 4 and the nth term is 4n+1
Un = (-1)n*(2n - 1)
The nth term is n2.
7n+4
n2
This is an Arithmetic Series/Sequence. In general the nth term, A(n) = a + (n - 1)d....where a is the 1st term and d is the common difference. In this question, the 1st term equals 1 and the common difference is 4. Then the nth term, A(n) = 1 + (n - 1) x 4 = 1 + 4n - 4 = 4n - 3.
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
tn = n2
n^2 + 2n + 1
4 Four Qutro The correct answer is: The nth term is 4n + 1
The nth term of the sequence is 2n + 1.
The given sequence is an arithmetic sequence with a common difference of 4 between each term. To find the nth term of an arithmetic sequence, we use the formula: nth term = a + (n-1)d, where a is the first term, d is the common difference, and n is the term number. In this case, the first term (a) is -3, the common difference (d) is 4, and the term number (n) is the position in the sequence. So, the nth term of the given sequence is -3 + (n-1)4 = 4n - 7.
n-squared, or n to the power 2
n+4