xn = xn-1 - (n + 2).
3n(n+1] + 5 is the nth term
The sequence 3, 8, 13, 18, 23, 28 increases by 5 each time. This indicates a linear pattern. The nth term can be expressed as ( a_n = 3 + 5(n - 1) ), which simplifies to ( a_n = 5n - 2 ). Thus, the nth term of the sequence is ( 5n - 2 ).
To find the nth term of the sequence 4, 13, 28, 49, 76, we first identify the differences between consecutive terms: 9, 15, 21, 27. The second differences, which are constant at 6 (6, 6, 6), suggest that the sequence is quadratic. The nth term can be expressed as ( an^2 + bn + c ). By solving the equations based on the first few terms, we find the nth term is ( n^2 + 3n ).
The Nth term in the series is [ 2N ] .
xn = xn-1 - (n + 2).
3n(n+1] + 5 is the nth term
It is: nth term = -4n+14
t(n) = n2 + 5n - 1
It is: nth term = 7n-9
The nth term is (2n - 12).
The Nth term in the series is [ 2N ] .
The nth term of the sequence is (n + 1)2 + 2.
The nth term is 5n-3 and so the next term will be 22
The nth term is 9n-2
The nth term is 2 + 3n.
The nth term is 3n+2 and so the next number will be 17