The sequence 2, 9, 28, 65 can be generated by the formula ( n^3 - n ), where ( n ) represents the position in the sequence (starting from ( n = 1 )). Thus, the nth term can be expressed as ( n^3 - n ). For example, for ( n = 1 ), ( 1^3 - 1 = 0 ); for ( n = 2 ), ( 2^3 - 2 = 6 ); and so on, aligning with the given sequence.
To find the nth term of the sequence 4, 10, 18, 28, 40, we first identify the pattern in the differences between consecutive terms: 6, 8, 10, and 12. The second differences are constant at 2, indicating a quadratic sequence. The nth term can be expressed as ( a_n = n^2 + n + 2 ). Thus, the nth term of the sequence is ( n^2 + n + 2 ).
xn = xn-1 - (n + 2).
3n(n+1] + 5 is the nth term
The sequence 3, 8, 13, 18, 23, 28 increases by 5 each time. This indicates a linear pattern. The nth term can be expressed as ( a_n = 3 + 5(n - 1) ), which simplifies to ( a_n = 5n - 2 ). Thus, the nth term of the sequence is ( 5n - 2 ).
To find the nth term of the sequence 4, 13, 28, 49, 76, we first identify the differences between consecutive terms: 9, 15, 21, 27. The second differences, which are constant at 6 (6, 6, 6), suggest that the sequence is quadratic. The nth term can be expressed as ( an^2 + bn + c ). By solving the equations based on the first few terms, we find the nth term is ( n^2 + 3n ).
To find the nth term of the sequence 4, 10, 18, 28, 40, we first identify the pattern in the differences between consecutive terms: 6, 8, 10, and 12. The second differences are constant at 2, indicating a quadratic sequence. The nth term can be expressed as ( a_n = n^2 + n + 2 ). Thus, the nth term of the sequence is ( n^2 + n + 2 ).
xn = xn-1 - (n + 2).
3n(n+1] + 5 is the nth term
The sequence 3, 8, 13, 18, 23, 28 increases by 5 each time. This indicates a linear pattern. The nth term can be expressed as ( a_n = 3 + 5(n - 1) ), which simplifies to ( a_n = 5n - 2 ). Thus, the nth term of the sequence is ( 5n - 2 ).
It is: nth term = -4n+14
t(n) = n2 + 5n - 1
To find the nth term of the sequence 4, 13, 28, 49, 76, we first identify the differences between consecutive terms: 9, 15, 21, 27. The second differences, which are constant at 6 (6, 6, 6), suggest that the sequence is quadratic. The nth term can be expressed as ( an^2 + bn + c ). By solving the equations based on the first few terms, we find the nth term is ( n^2 + 3n ).
It is: nth term = 7n-9
The nth term is (2n - 12).
The Nth term in the series is [ 2N ] .
The nth term of the sequence is (n + 1)2 + 2.
To find the nth term of the sequence 4, 7, 12, 19, 28, we first look at the differences between consecutive terms: 3, 5, 7, 9, which suggests a pattern of increasing odd numbers. The second differences are constant, indicating a quadratic function. The nth term can be expressed as ( T(n) = n^2 + n + 2 ). Thus, for any term n, you can calculate its value using this formula.