10 Hz
2 x 10 to power 6 cycles in 1 sec. Period is (1) / (2 x 10 to power 6) = (0.5) x (10 to the power -6) = 0.5 microseconds
Period = 1/FrequencySo if we set Frequency = x THEN:10 = 1/x10x = 1x = 1/10IF Period of a Wave is 10 Seconds THEN The Frequency =1/10 or .10
Frequency = 1/period1/7.5 x 10-3 = 1331/3 Hz = 2/15 KHz
If you mean a wave that has a frequency of 10 hz at 360 m/s, then the answer is 1/36 of a second. The period is the inverse of the wavelength and the wavelength is equal to the wave speed divided y the frequency. 360/10=36 and the inverse of 36 is 1/36.
10 Hz
frequency of 10 hertz
10kHz = 10,000 s^-1 This means that the wave makes 10,000 ( ten thousand ) cycles in 1 second. So 100 cycles is made in 100/10000 s 1/100 s or 0.01 s. NB remember k = kilo ( or one thousand) The S.I. unit for Hertz (Hz) is 'per second/ s^-1)
The length of a radio wave at 900 kHz is 3331/3 meters, or about 1093.6 feet.
2 x 10 to power 6 cycles in 1 sec. Period is (1) / (2 x 10 to power 6) = (0.5) x (10 to the power -6) = 0.5 microseconds
For a sine wave, the RMS is the amplitude divided by square root of 2. The amplitude is 10 cm. in this case; so the exact value is 10 / root(2), or about 7.For a sine wave, the RMS is the amplitude divided by square root of 2. The amplitude is 10 cm. in this case; so the exact value is 10 / root(2), or about 7.For a sine wave, the RMS is the amplitude divided by square root of 2. The amplitude is 10 cm. in this case; so the exact value is 10 / root(2), or about 7.For a sine wave, the RMS is the amplitude divided by square root of 2. The amplitude is 10 cm. in this case; so the exact value is 10 / root(2), or about 7.
To draw a 1 GHz sine wave with a period of 1, you can set up the equation y = sin(2π * 10^9 * x). This equation represents a sine wave with a frequency of 1 GHz (1 billion cycles per second) and a period of 1 time unit. You can then use graphing software or tools to plot this sine wave accurately.
Well, a pure sine wave can only be produced as a pure sine wave. If it was modified to begin with, it would never be a pure sine wave. However, an actual generator should be supplying pure sine wave output, while something such as an inverter would be producing a modified sine wave.
BW = (1 MHz - 10 KHz) = (1,000 KHz - 10 KHz) = 990 KHz
5 cycles.
Period = 1/FrequencySo if we set Frequency = x THEN:10 = 1/x10x = 1x = 1/10IF Period of a Wave is 10 Seconds THEN The Frequency =1/10 or .10
Frequency = 1/period1/7.5 x 10-3 = 1331/3 Hz = 2/15 KHz