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8 out 1
If the die is a regular octahedron, then the probability for each face is 1/8.
The probability to get heads once is 1/2 as the coin is fair The probability to get heads twice is 1/2x1/2 The probability to get heads three times is 1/2x1/2x1/2 The probability to get tails once is 1/2 The probability to get tails 5 times is (1/2)5 So the probability to get 3 heads when the coin is tossed 8 times is (1/2)3(1/2)5=(1/2)8 = 1/256 If you read carefully you'll understand that 3 heads and 5 tails has the same probability than any other outcome = 1/256 As the coin is fair, each side has the same probability to appear So the probability to get 3 heads and 5 tails is the same as getting for instance 8 heads or 8 tails or 1 tails and 7 heads, and so on
It is 4/8 = 1/2
The first thing to do is isolate how many ways there are to get 8 from two dice. These possibilities are:2,63,54,45,36,2so there are 5 possibilities. The probability of each of these combinations is (1/6)2 or 1/36, so the probability of getting 8 in one throw of 2 dice is 5/36For 9 throws, it is easier to calculate the probability of never getting 8. This is (1-probability of getting 8)9. (1-5/36)9 = (31/36)9 which is 0.26033. So the probability of getting an 8 somewhere along the line is 1-0.26033 or 0.7397