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To find the probability of being dealt exactly 4 aces in a 13-card hand from a standard 52-card deck, we can use the hypergeometric distribution. The total number of ways to choose 4 aces from 4 available is ( \binom{4}{4} = 1 ), and the number of ways to choose the remaining 9 cards from the 48 non-aces is ( \binom{48}{9} ). The total number of ways to choose any 13 cards from 52 is ( \binom{52}{13} ). Thus, the probability is given by ( \frac{1 \times \binom{48}{9}}{\binom{52}{13}} ).
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What is the probability of beind dealt five aces from a standard 52 card deck?
Since there are only four aces in a standard 52 card deck, the probability of being dealt five aces is zero.
What is the probability of getting a face card or a 7 or a diamond from an ordinary deck of cards?
There is a .53846 probability (53.846%) if aces are counted as face cards. If they are not counted the probability drops to .48077 (48.077%)
What is the probability of getting 4 ace?
To get four Aces it is necessary to draw several cards. There is no information on how many cards are drawn. Whether or not they are drawn randomly.
Find the probability of getting four consecutive aces when four cards are drawn without replacement from a deck of 52 cards?
The probability of drawing four aces in a draw of four cards from a deck of 52 cards is 3 in 812175. (4 in 52) times (3 in 51) times (2 in 50) times (1 in 49)
The probability that two cards drawn from a deck of cards are both aces?
The probability of drawing two Aces from a standard deck of 52 cards is 4 in 52 times 3 in 51, or 12 in 2652, or 1 in 221, or about 0.00452.
