1/10
1/8 or .125 or 12.5%
The probability of spinning the spinner and landing on an odd number depends on the number of odd numbers on the spinner and the total number of numbers on the spinner. If there are 3 odd numbers on the spinner and a total of 6 numbers, then the probability of landing on an odd number is 3/6, which simplifies to 1/2 or 50%.
To determine the probability of the spinner landing on an even number, you need to know the total number of sections on the spinner and how many of those sections contain even numbers. The probability is calculated by dividing the number of even-numbered sections by the total number of sections. For example, if the spinner has 8 sections numbered 1 through 8, there are 4 even numbers (2, 4, 6, 8), resulting in a probability of 4/8 or 1/2.
7
To determine the probability of the spinner landing on B and then C, we need to know the individual probabilities of landing on B and C. Assuming the spinner is fair and has an equal number of sections for A, B, and C, the probability of landing on B is 1/3, and the probability of landing on C is also 1/3. Thus, the combined probability of landing on B first and then C is (1/3) * (1/3) = 1/9.
9
The probability is one in four, or 25%.
The probability is 3/7.
The probability is 5/9.
1/8 or .125 or 12.5%
6-52
The probability of spinning the spinner and landing on an odd number depends on the number of odd numbers on the spinner and the total number of numbers on the spinner. If there are 3 odd numbers on the spinner and a total of 6 numbers, then the probability of landing on an odd number is 3/6, which simplifies to 1/2 or 50%.
The answer depends on the number of sides on the spinner and what numbers are on it.
7
If it is a fair spinner, then 3/8
1/2
To determine the probability of the spinner landing on B and then C, we need to know the individual probabilities of landing on B and C. Assuming the spinner is fair and has an equal number of sections for A, B, and C, the probability of landing on B is 1/3, and the probability of landing on C is also 1/3. Thus, the combined probability of landing on B first and then C is (1/3) * (1/3) = 1/9.