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The answer depends on the number of sides on the spinner and what numbers are on it.

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What is the probability of the spinner landing on 1 or 4?

1 and 4


What is the probability of landing on number 4 if you spun a spinner numbered 1 through 4?

The probability is one in four, or 25%.


What is the probability of a spinner landing on an even number 1-8?

It is 4/8 = 1/2


What is the probability of landing on number 4 if you spun a spinner numbered 1 through 8?

1/8 or .125 or 12.5%


How do you find the probability of a spinner?

You find out how many choices there are in a spinner and then you take what it wants you to find the probability of and tur it into a fraction For example: You have a spinner with 4 triangles in it....2 are red and 2 are green,What is the probability of landing on a green triangle 2 out of 4


If you have a spinner with white black and stripes on it what is the probability that the spinner will land on the black space twice?

The probability of landing on black twice on a spinner with white, black, and striped sections is (1/3)^2 = 1/9. This is because there is a 1/3 chance of landing on black on each spin, and the spins are independent events.


What is the probability that the spinner will stop on 1-4?

The depends on what other numbers exist on the spinner. If there are a total of six numbers on the spinner, for instance, the probability of spinning a 1-4 is 2 in 3.


If you spin the spinner two times what is the probability that the spinner will land on the black region twice?

To calculate the probability of spinning the black region twice on a spinner, you first need to determine the total number of possible outcomes when spinning the spinner twice. Let's say the spinner has 8 equal sections, with 2 black regions. The total outcomes for spinning the spinner twice would be 8 x 8 = 64. The probability of landing on the black region twice would be 2/8 x 2/8 = 4/64 = 1/16. Therefore, the probability of landing on the black region twice is 1/16 or approximately 0.0625.


What is the probability of spinning a spinner that has 5 equal sections marked 1 through 5 and landing on an even number?

The spinner has five equal sections marked 1 through 5, with the even numbers being 2 and 4. There are 2 favorable outcomes (landing on an even number) out of a total of 5 possible outcomes. Therefore, the probability of landing on an even number is ( \frac{2}{5} ) or 40%.


What is the probability of spinning a 3 on a four sided spinner?

Assuming that the four-sided spinner is fair and that it is numbered in the traditional way of 1, 2, 3 and 4, the probability of spinning a three is 1/4.


What is the probability of this spinner stopping on 3 out of 4?

75% probability


What is the probability that you will spin a 4 and roll a 4?

Assuming each possible number on a spinner has the same probability and an unbiased die is being rolled, the answer depends on how many numbers are on the spinner, and how many times the number 4 appears on each.To find the probability, workout the probability of spinning a 4 on the spinner and the probability of rolling a 4 on the die; then as spinning the spinner has no effect on rolling the die, they are independent events and to get the probability of both happening multiply them together.The probability of success is the number of successful outcomes divided by the total number of outcomes, giving:Probability(spinning a 4) = how_many_4s_are_on_the_spinner / how_many_numbers_are_on_the_spinnerProbability(rolling a 4) = how_many_4s_are_on_the_die / how_many_numbers_are_on_the_dieProbability(spinning a 4 and rolling a 4) = Probability(spinning a 4) × Probability(rolling a 4)Examples:an octagonal spinner with the numbers 1-4 on it each twice and a tetrahedral die (as used in D&D games) with the numbers 1-4 on it→ pr(spin 4 & roll 4) = 2/8 × 1/4 = 1/16a decagonal spinner with the numbers 0-9 and a tetrahedral die with the numbers 0-3 on it→ pr(spin 4 & roll 4) = 1/10 × 0/4 = 0a decagonal spinner with the numbers 0-9 and a standard die with the numbers 1-6 on it→ pr(spin 4 & roll 4) = 1/10 × 1/6 =1/60

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