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A jar contains 22 yellow marbles 26 green marbles 17 red marbles and 20 purple marbles A marble is drawn at random what is the probability of not pulling out a purple marble?
probability of pulling out a purple marble = 20/85probability of NOT pulling out a purple marble = 1 - 20/85 = 65/85 = 13/17
A bag has 13 green marbles What is the probability pf drawing out a green marble?
your probability would be 13/13. you would have a 100 percent chance of getting a green marble
What is the probability of 3 green marbles?
the probability is you'd get a green marble any other color is impossible. So, the probability is certain
What is the experimental probability of choosing a green marble if there are 7 red 9 yellow 14 green and 10 purple?
To find the experimental probability of choosing a green marble, first calculate the total number of marbles: 7 red + 9 yellow + 14 green + 10 purple = 40 marbles. The probability of choosing a green marble is the number of green marbles divided by the total number of marbles, which is 14 green / 40 total = 0.35. Thus, the experimental probability of choosing a green marble is 0.35, or 35%.
What is the probability of pulling a yellow-green marble out of the bag?
It depends on how many yellow-green marbles there are, and on how many total marbles there are. There is insufficient information in the question to answer it. Please restate the question, giving this other information.
A jar contains 22 yellow marbles 26 green marbles 17 red marbles and 20 purple marbles A marble is drawn at random what is the probability of not pulling out a purple marble?
probability of pulling out a purple marble = 20/85probability of NOT pulling out a purple marble = 1 - 20/85 = 65/85 = 13/17
A bag has 13 green marbles What is the probability pf drawing out a green marble?
your probability would be 13/13. you would have a 100 percent chance of getting a green marble
What is the probability of 3 green marbles?
the probability is you'd get a green marble any other color is impossible. So, the probability is certain
What is the experimental probability of choosing a green marble if there are 7 red 9 yellow 14 green and 10 purple?
To find the experimental probability of choosing a green marble, first calculate the total number of marbles: 7 red + 9 yellow + 14 green + 10 purple = 40 marbles. The probability of choosing a green marble is the number of green marbles divided by the total number of marbles, which is 14 green / 40 total = 0.35. Thus, the experimental probability of choosing a green marble is 0.35, or 35%.
What is the answer to the experimental probability of pulling out a green marble if you got 5 green 6 blue and 9 red in the tally chart?
5/(5+6+9) = 5/20 = 1/4 or 0.25
What is the probability of pulling a yellow-green marble out of the bag?
It depends on how many yellow-green marbles there are, and on how many total marbles there are. There is insufficient information in the question to answer it. Please restate the question, giving this other information.
What is the probability of choosing blue marble followed by a green marble from a bag containing 5 blue 5 green and 5 red marbles?
The probability of choosing a blue marble is 5 in 15 or 1 in 3. The probability of then choosing a green marble is 5 in 14. (One is missing) Multiply the two probabilities and you get 5 in 42.(P = 0.1190... about 12%).
There are 4 bags each containing 4 red marbles and 1 green marble If you grab one marble from each bag what is the probability of grabbing at least 2 green marbles?
Let's consider first one bag: The probability to grab one green marble is Pg=1/5 The probability to grab one red marble is Pr=1-Pg=4/5 For the 4 bags, it's a binomial distribution: probability to get k green out of n bags, P(X=k)=nCk pk (1-p)n-k = nCk Pgk Prn-k Now, the probability to grab at least 2 green marbles from 4 bags is 1 - (Probability to get no green marble from 4 bags) - (Probability to get just one green marble from 4 bags) Probability to get no green marble is = 4C0 (4/5)4 = (4/5)4 (n=4, k=0, no green marble from each bag, 4C0 Pr4) Probability to get just one green marble is = 4C1 (1/5) (4/5)3 (n=4, k=1, one green marble from one bag and red marbles from the other ones, 4C1 Pg Pr3) Probability to grab at least 2 green marbles from 4 bags is 1-(4/5)4-4*(1/5)(4/5)3 = 0.1801
What is the probability of getting a green marble?
To determine the probability of getting a green marble, you need to know the total number of marbles and the number of green marbles specifically. The probability is calculated by dividing the number of green marbles by the total number of marbles. For example, if there are 5 green marbles out of 20 total marbles, the probability would be 5/20, which simplifies to 1/4 or 25%.
How likely are you to pull a red or yellow marble out of a bag of 3 green 8 red 8 yellow and 3 black marbles?
The probability of pulling a red or yellow marble out of a bag of 3 green 8 red 8 yellow and 3 black marbles is 16 out of 22, or about 0.73.
What is the probability of choosing a marble that is not blue out of 5 red and 6 green?
100%
What is the probability of not choosing a green marble from a jar containing 5 red 6 green and 4 blue marbles?
This is the same as the probability of choosing either a red of a blue marble. There are 5+4 out of 15 ways of doing this. The probability is therefore 9/15 = 3/5.
