The probability that exactly 4 out of 6 randomly selected vehicles will pass the test when the pass rate is 80% is approx 0.2458 (or nearly a quarter).
Using the Poisson approximation, the probability is 0.0418
Approx 0.0287
You multiply the probability by 100.
pr(exactly 4 out of 8 cured) = ₈C₄ × (98/100)⁴ × (1 - 98/100)⁴ = 103305233920/10000000000000000 ≈ 0.00001
80%
The probability is 10 percent.
Only one selected 68%
The probability is approx 0.81
Using the Poisson approximation, the probability is 0.0418
Approx 0.0287
It is 0.73 = 0.343
The probability that both will be hopelessly romantic is .0081 .009^2 = .0081
0.6382
The probability of 33.3 percent is 0.333.
probability of 75 percent = 3/4
The probability the shooter makes both shots is .7 * .7 = .49, and the probability of making neither is .3 * .3 = .09. So the probability of making exactly 1 out of 2 is 1 - .49 - .9 = .42, or 42 percent.
You multiply the probability by 100.