The probability is 5/6.
The die has 6 sides so 5 of them are not the "4". The probability of getting the four is 1/6.
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If there are four colors on a spinner, then the probability of spinning one particular color is 1 in 4, or 0.25. Also, the probability of spinning one of two particular colors is 2 in 4, or 0.5. Combining these two "unrelated" events simply requires multiplication. The probability, then, of spinning one particular color on one spin, and then spinning one of two particular colors on the next spin is (1 in 4) times (2 in 4), or 2 in 16, or 0.125.
On one spin, and assuming the spinner is fair, 1/6
Assuming the numbers on the spinner are all given the same amount of space on the spinner, there is a 1:4 chance of spinning a 4. In other words, a 25% chance you spin a 4.
Assuming the spinner has sections numbered 1-5 then: Pr(Spin < 4) = 3/5 (= 0.6 or 60%) Pr(Roll > 4) = 3/6 = 1/2 (= 0.5 or 50%) Assuming both done together: Pr(spin < 4 or roll < 4) = Pr(spin < 4) + Pr(roll < 4) - Pr(spin < 4 and roll < 4 [at same time]) = 3/5 + 1/2 - 3/5 × 1/2 = 6/10 + 5/10 - 3/10 = 8/10 = 4/5 (= 0.8 or 80%) It can also be calculated out by working out the probability of not spinning less than 4 and not rolling less than 4 (at the same time), and then subtracting this from 1 (or 100%): Pr(spin < 4 or roll < 4) = 1 - Pr(spin ≥ 4 and roll ≥ 4) = 1 - (1 - 3/5) x (1 - 1/2) = 1 - 2/5 x 1/2 = 1 - 1/5 = 4/5 (= 0.8 or 80%)
The probability of spinning the number 3, or any number, is 1/4 or 0.25 since there is 4 numbers total.