Yes and the quotient is exactly 80997
293 is not divisible by 5. Only numbers that end on 0 or 5 are exactly divisible by 5.No, it is not.
Yes! and the quotient is 47
Largest no of 5 digits is 99999 99999/99 gives 1010 quotient 9 as remainder 99999-9=99990 is the largest 5 digit no divisible by 99.
Not exactly because it will have remainder
Yes and the quotient is exactly 80997
293 is not divisible by 5. Only numbers that end on 0 or 5 are exactly divisible by 5.No, it is not.
Yes! and the quotient is 47
Largest no of 5 digits is 99999 99999/99 gives 1010 quotient 9 as remainder 99999-9=99990 is the largest 5 digit no divisible by 99.
1435 is divisible by 5.1435 ÷ 5 = 287 (The quotient doesn't have a remainder.)
yes the answer is 12
Yes, but not evenly, quotient is 5 and remainder is 1
Yes, but not evenly, quotient is 5057, remainder is 4
Nope, 10 is divisible by 5, 2, and 1. You are looking for the number 12. 12 is divisible by 6.
403÷8 gives 50 as quotient and 3 as remainder. Dividend- remainder=divisor ×quotient 403-3=8*50 which is 400. our value is 403 So increase divisor 8*51=408. 403+5 gives 408. So 5 must be added to 403 to get a no divisible by 8.
16
1, 2, 4, 5, and 10