10 adults & 10 children's
The formula to determine the total money is nA + mC = 1317.50 where n is the number of adult tickets sold and A is the price of the adult tickets and m OS the number of child tickets and C is the price of a child ticket. Substituting in the actual prices we get... eq 1. n*7.50 + m * 3.50 = 1317.50 eq 2. n+m = 205 rearranging eq 2 we get n = 205 - m substituting this into eq 1 we get.. (205 -m) * 7.5 + m * 3.5 = 1317.50 Simplifying we get 1537.5 - 7.5m + 3.5m = 1317.50 1537.5 - 1317.5 = 4m 220 = 4m 55 = m substituting into eqn 2 we get n + 55 = 205 n = 150. Therefor 150 Adult tickets were sold 55 Child tickets were sold
I'll try to explain it.We know that an adult's ticket is two times the cost of a child's ticket. We will call the child's ticket "y". If we do so, the adult's ticket will be 2"y" because it's two times the cost of a child's ticket. We also know that the total cost is 28. Now, we'll write an equation, knowing the number of children and adults and the relationship between the costs:2*2y will be the two adult's tickets.3*y will be the three children's tickets.The equation:2*2y+3*y=284y+3y=287y=28y=4Now, we know that ONE child's ticket costs 4. To find out how much an adult's ticket costs, we have to double it (look at the exercise, it says that an adult's ticket is two times the cost of a child's ticket).4*2=8Finally, we've found out that a child's ticket costs 4 and an adult's ticket costs 8.We can check it as well:2*8+3*4=16+12=28
It costs 15.00 for two adults and two children.
Ok Let Children=C Let Adult=A Set up two equations: 3C+9A=$1905 C+A=419 tickets Solve the second equation for C or A, I'm choosing A A=419-C Sub it into the other equation 3C+9(419-C)=1905 3C+3771-9C=1905 Distribute 3771-6C=1905 Combine like terms -6C=(-1866) Subtract 3771 from both sides C=311 Divide by -6 Take 311 and plug it into the other equation "C+A=419" to find A=108 Answer Sold 108 adult tickets and 311 child tickets
adult:£7.50 child:£5.00
7 Adult tickets 13 Child tickets
10 adults & 10 children's
1-Day Park Hopper$940 total ($97 each for adult tickets, $87 each for child tickets)1-Day 1-Park$690 total ($72 each for adult tickets, $62 each for child tickets)
Yes, child plane tickets are often cheaper than adult plane tickets, as airlines usually offer discounted fares for children under a certain age. However, the exact pricing may vary depending on the airline and specific flight.
Adult tickets are $9.50 Senior tickets are $7.00 Child tickets are $7.50
The tickets are $5 adult and $2 child. Here is the algebraic substitution. A = adult ticket money C = child ticket money 120C + 80A = 640 C = A-3 (three dollars less) 120 (A-3) + 80A = 640 120 A - 360 + 80A = 640 200 A = 1000 A = 5 C = A - 3 = 2 Checking your answer: 120(2) + 80 (5) = 240 + 400 = 640
At Bella Terra there about $11.25 per adult and $8.25 per child
One-day One-park$426.60 ($71.10 each) for 6 adult tickets$367.20 ($61.20 each) for 6 child ticketsOne-day Park Hopper$582.60 ($97.10 each) for 6 adult tickets$523.20 ($87.20 each) for 6 child tickets
The formula to determine the total money is nA + mC = 1317.50 where n is the number of adult tickets sold and A is the price of the adult tickets and m OS the number of child tickets and C is the price of a child ticket. Substituting in the actual prices we get... eq 1. n*7.50 + m * 3.50 = 1317.50 eq 2. n+m = 205 rearranging eq 2 we get n = 205 - m substituting this into eq 1 we get.. (205 -m) * 7.5 + m * 3.5 = 1317.50 Simplifying we get 1537.5 - 7.5m + 3.5m = 1317.50 1537.5 - 1317.5 = 4m 220 = 4m 55 = m substituting into eqn 2 we get n + 55 = 205 n = 150. Therefor 150 Adult tickets were sold 55 Child tickets were sold
[100 + 54] 910 + 291.60 = 1,201.60 (too much) [90 + 64] 819 + 345.60 = 1,164.60 (too much) [80 + 74] 728 + 399.60 = 1,127.60 (too little) so answer is between 65 and 73 child tickets 1,135.00 - 1,127.60 = 7.40 9.10 - 5.40 = 3.70 7.40 / 3.70 = 2 so adjusting [80 + 74] by that 2 ... [82 + 72] 746.20 + 388.80 = 1,135.00 Answer: 72 child tickets (and 82 adult tickets)
For 1 park (Adventure Island) an adult ticket is $41.95 and for a child ticket it is $37.95, but if you want two parks (Adventure Island and Busch Gardens) it'll cost $89.95 for an adult and $79.95 for a child.