y=8x-12
General equation of a line Y=mx+c
Y= y axis
X=x axis
m= gradient (how steep the line is)
c= intercept (where the line crosses the y axis)
Coordinate geometry
Y=2x+6
(0,-6) m=-2
Point: (2, 17)Slope: 7Equation: y = 2x+13
Yes, I could, if I knew the slope of the line given.
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
sda
Coordinate geometry
Y=2x+6
Slope-intercept form
(0,-6) m=-2
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
Point: (2, 17)Slope: 7Equation: y = 2x+13
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
y=-3x-2
the Equation of a Line Given That You Know Two Points it Passes Through.