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If 'S' is the relationship between actual and scale linear dimensions,then 'S2' is the relationship between actual and scale areas.
rddffdg
The areas are proportional to the square of the scale factor.
Find the areas of the rectangles and triangles. Add them together.
You could consider the cross as two intersecting rectangles. Calculate the area of both rectangles and the area of the intersection (overlap). Then area of cross = sum of the areas of the rectangles minus the area of the overlap.
multiply the length with the breadth.
There is no relationship between the perimeter and area of a rectangle. Knowing the perimeter, it's not possible to find the area. If you pick a number for the perimeter, there are an infinite number of rectangles with different areas that all have that perimeter. Knowing the area, it's not possible to find the perimeter. If you pick a number for the area, there are an infinite number of rectangles with different perimeters that all have that area.
wht u hve to do is to cut the shape into rectangles and then times the length and width together on each rectangle. then add up all the rectangles areas and add them alll up. ta da
If 'S' is the relationship between actual and scale linear dimensions,then 'S2' is the relationship between actual and scale areas.
Rectangles are related to the distributive property because you can divide a rectangle into smaller rectangles. The sum of the areas of the smaller rectangles will equal the area of the larger rectangle.
In order to get a rectangle with an area of 24 centimeters, the length and width multiplied need to equal 24. On top of that, length and width may not be equal, or the shape would be a square instead of a rectangle. Examples of rectangles with 24cm areas: 1x24 cm 2x12 cm 3x8 cm 4x6 cm
Do you mean the surface area of the box? If so... What you do is break the surface area into 6 rectangles: Two rectangles have sides of length 6.3 and 12.6 inches. Two rectangles have sides of length 6.3 and 4.2 inches. Two rectangles have sides of length 12.6 and 4.2 inches. Find the area of each of the six rectangles (using the standard formula for the area of a rectangle, A = W x H), and add up all six. The sum of the areas of the six rectangles will be the surface area of the box. Since the lengths of the sides are in inches, the area will already be in square inches, and therefore you don't have to "turn it into square inches".
rddffdg
The areas are proportional to the square of the scale factor.
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An L-shaped area can be divided into two rectangles. The total area is the sum of the areas of the two rectangles.