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You need an equation for the nth term of the sequence, or some other means of identifying the sequence. In general, they will be a+n, a+2n, a+3n and a+4n although some go for a, a+n, a+2n and a+3n.
3925
There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2
nth term
The question does not contain a sequence but a single large number whose digits are the digits of the sequence, 3n run together. There is only one number, not a sequence, so there is no nth term.
123456789 * * * * * The nth term is 3n
It is an arithmetic progression. Elements of the sequence can be identified by substituting the values of n in the expression 3n + 5
The nth term of the sequence is 3n - 2.
7
3,6,9,12.....
You need an equation for the nth term of the sequence, or some other means of identifying the sequence. In general, they will be a+n, a+2n, a+3n and a+4n although some go for a, a+n, a+2n and a+3n.
4
8
Finding the nth term is much simpler than it seems. For example, say you had the sequence: 1,4,7,10,13,16 Sequence 1 First we find the difference between the numbers. 1 (3) 4 (3) 7 (3) 10 (3) 13 (3) 16 The difference is the same: 3. So the start of are formula will be 3n. If it was 3n, the sequence would be 3,6,9,12,15,18 Sequence 2 But this is not our sequence. Notice that each number on sequence 2 is 2 more than sequence 1. this means are final formula will be: 3n+1 Test it out, it works!
To find the 8th term of the sequence with the rule 3n + 4, you would substitute n = 8 into the formula. This gives you 3(8) + 4 = 24 + 4 = 28. Therefore, the 8th term of the sequence is 28.
16
3925