2(y - 3)(y - 10)
10x2y2 + 8xy2 - 210y2 = 2y2(5x2 + 4x - 105) = 2y2(5x2 + 25x - 21x - 105) = 2y2(x + 5)(5x - 21).
The y-intercept is the place (or places) where x=0 . So if 'x' is 2y2+3y+1 , then all you have to do is find places where 2y2+3y+1 is zero, and those are your y-intercepts.
All six of them
5x2 - 2y2 = -20 7x2 - y2 = 152 Eq1 - 2*Eq2: -9x2 = -324 so that x2 = 36 Substituting the value of x2 in Eq1: 2y2 = 200 so that y2 = 100 The four solutions are (-6, -10), (-6, 10), (6, -10) and (6,10)
2(y - 3)(y - 10)
It is a cubic function of y.
this equals to 12
y2 + y2 = 2y2
10x2y2 + 8xy2 - 210y2 = 2y2(5x2 + 4x - 105) = 2y2(5x2 + 25x - 21x - 105) = 2y2(x + 5)(5x - 21).
The y-intercept is the place (or places) where x=0 . So if 'x' is 2y2+3y+1 , then all you have to do is find places where 2y2+3y+1 is zero, and those are your y-intercepts.
All six of them
5x2 - 2y2 = -20 7x2 - y2 = 152 Eq1 - 2*Eq2: -9x2 = -324 so that x2 = 36 Substituting the value of x2 in Eq1: 2y2 = 200 so that y2 = 100 The four solutions are (-6, -10), (-6, 10), (6, -10) and (6,10)
5(x + 2y2)(x2 - 2xy2 + 4y4)
Oh, dude, y squared plus y squared equals 2y squared. It's like adding two of the same things together, you know? So, if you have y squared and add another y squared, you end up with 2y squared. Math can be pretty chill sometimes, huh?
1
Yes, 18y3 + 2y2 + 1 is a polynomial; it is a cubic expression. If it were expanded to form an equation, then it would be a cubic equation (or higher), capable of solution.