First, give them a common denominator by multiplying (x-3) and (3-x), which gives you -1(x-3)^2.
Then, you have to multiply the first 3 of the numerator with (3-x) and x with (x-3). This will give you x^2-6x+9 over -(x-3)^2, which will simplify to (x-3)^2 over -(x-3)^2.
The top and the bottom of the fraction will simplify and give you 1 over -1, which is simply:
-1.
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1-3x1=3x 1/3=x
x3 + 2x2 + 3x + 6 = x2(x + 2) + 3(x + 2) = (x + 2)(x2 + 3)
The Answer:The sum of cubes, operation is: (a+b)(a2-ab+b2) = a3+b3So, since 27 = 33 we can reformulate to:So, x3+33 = (x + 3)(x2-3x+32) = (x + 3)(x2-3x+9).
(x-2)(x^2+3)
(X + 1)3 = X3 + 3X2 + 3X + 1