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What is the sum of m a and m b?
ma + mb = m(a + b) this is an algebra formule, what cyfers, NUMBERS STAND A and M for I suspect that slashes representing fractions are missing: m/a + m/b = mb + ma/ab = m(b + a)/ab
How do you prove that the exterior angle of a triangle is equal to the sum of the two opposite interior angles?
Assume a triangle ABC with a line AB (containing the side AB) with external angle D which is formed when line AB and line segment AC intersect. We are asked to prove that the external angle D is equal to the sum of the two interior angles B and C. Angles A and D are supplementary angles (they sum to 180 degrees) because they are linear angles (both together make a straight line, or a 180 degree angle). This means: m<A + m<D = 180 degrees. m<A = 180 deg - m<D Then because A, B, and C are the three angles in a triange: m<A + m<B + m<C = 180 deg m<A = 180 deg - m<B - m<C By substituting 180 deg - m<D in for m<A in the above equation we get: 180 deg - m<D = 180 deg - m<B - m<C Subtract 180 deg from each side: -m<D = -m<B - m<C Multiply both sides by -1 m<D = m<B + m<C Which proves that the measure of the external angle D is equal to the sum of the two opposite interior angles B and C for any given triangle. wow. that's a lot. lol.
How do you write a line in point-slope form?
The equation of a line passing through a point P with coordinates (a,b) and slope m is (y-b) = m(x-a) changing that to the more conventional form: y = mx + (b - ma)
How do you find the slope intercept form from 2 set of points?
Suppose the two points are (a,b) and (c,d) then the slope is (b-d)/(c-a). Write that as m. Then the equation of the line is y-b = m(x-a) which can be simplified to y = mx + b-ma
How do you solve of sum and different of two terms?
To solve the sum and difference of two terms, you can use the identities for the sum and difference of squares. For two terms (a) and (b), the sum is expressed as (a + b) and the difference as (a - b). To find their product, you use the formula: ((a + b)(a - b) = a^2 - b^2). This allows you to calculate the difference of squares directly from the sum and difference of the terms.
What is the sum of m a and m b?
ma + mb = m(a + b) this is an algebra formule, what cyfers, NUMBERS STAND A and M for I suspect that slashes representing fractions are missing: m/a + m/b = mb + ma/ab = m(b + a)/ab
How do you change point-slope to slope-intercept?
Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.
How do you find the x intercept when you have slope and a point?
Obtain the coordinates of the point (a,b) Utilise the standard equation for a straight line y = mx + c The slope 'm' is known. Substituting a, b for x, y then b = ma + c : c = b - ma The equation now becomes y = mx + (b - ma) The x intercept occurs when y = 0 : substituting this gives :- 0 = mx + (b - ma) : mx = ma - b : x = (ma - b) ÷ m EXAMPLE : Slope is 5, Point coordinates are (2,4): x intercept = [(5 x 2) - 4] ÷ 5 = 6 ÷ 5 = 1.2
The sum of 38 and m?
Sum = 38 + M
How do you prove that the exterior angle of a triangle is equal to the sum of the two opposite interior angles?
Assume a triangle ABC with a line AB (containing the side AB) with external angle D which is formed when line AB and line segment AC intersect. We are asked to prove that the external angle D is equal to the sum of the two interior angles B and C. Angles A and D are supplementary angles (they sum to 180 degrees) because they are linear angles (both together make a straight line, or a 180 degree angle). This means: m<A + m<D = 180 degrees. m<A = 180 deg - m<D Then because A, B, and C are the three angles in a triange: m<A + m<B + m<C = 180 deg m<A = 180 deg - m<B - m<C By substituting 180 deg - m<D in for m<A in the above equation we get: 180 deg - m<D = 180 deg - m<B - m<C Subtract 180 deg from each side: -m<D = -m<B - m<C Multiply both sides by -1 m<D = m<B + m<C Which proves that the measure of the external angle D is equal to the sum of the two opposite interior angles B and C for any given triangle. wow. that's a lot. lol.
The sum of 3 times m and n?
the sum of 3 times m and n
what id the sum of m and 6?
The sum of "m" and 6 is "m + 6".
How do you write a line in point-slope form?
The equation of a line passing through a point P with coordinates (a,b) and slope m is (y-b) = m(x-a) changing that to the more conventional form: y = mx + (b - ma)
How do you find the slope intercept form from 2 set of points?
Suppose the two points are (a,b) and (c,d) then the slope is (b-d)/(c-a). Write that as m. Then the equation of the line is y-b = m(x-a) which can be simplified to y = mx + b-ma
Rearrange F equals ma?
F = MA M = F / A A = F / M
What about nested for loop?
Possible. Example: void mat_mul (int m, int n, int l, const int **a, const int **b, int **c) { int i, j, k; double sum; for (i=0; i<m; ++i) { for (j=0; j<l; ++j) { sum= 0; for (k=0; k<n; ++k) { sum += a[i][k] * b[k][j]; } c[i][j]= sum; } }
What is the sum of mA and mB?
180 degress
