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It is mA + mB
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What is the sum of m a and m b?
ma + mb = m(a + b) this is an algebra formule, what cyfers, NUMBERS STAND A and M for I suspect that slashes representing fractions are missing: m/a + m/b = mb + ma/ab = m(b + a)/ab
How do you prove that the exterior angle of a triangle is equal to the sum of the two opposite interior angles?
Assume a triangle ABC with a line AB (containing the side AB) with external angle D which is formed when line AB and line segment AC intersect. We are asked to prove that the external angle D is equal to the sum of the two interior angles B and C. Angles A and D are supplementary angles (they sum to 180 degrees) because they are linear angles (both together make a straight line, or a 180 degree angle). This means: m<A + m<D = 180 degrees. m<A = 180 deg - m<D Then because A, B, and C are the three angles in a triange: m<A + m<B + m<C = 180 deg m<A = 180 deg - m<B - m<C By substituting 180 deg - m<D in for m<A in the above equation we get: 180 deg - m<D = 180 deg - m<B - m<C Subtract 180 deg from each side: -m<D = -m<B - m<C Multiply both sides by -1 m<D = m<B + m<C Which proves that the measure of the external angle D is equal to the sum of the two opposite interior angles B and C for any given triangle. wow. that's a lot. lol.
How do you write a line in point-slope form?
The equation of a line passing through a point P with coordinates (a,b) and slope m is (y-b) = m(x-a) changing that to the more conventional form: y = mx + (b - ma)
How do you find the slope intercept form from 2 set of points?
Suppose the two points are (a,b) and (c,d) then the slope is (b-d)/(c-a). Write that as m. Then the equation of the line is y-b = m(x-a) which can be simplified to y = mx + b-ma
What is the sum of b and 5?
(b+5)
What is the sum of m a and m b?
ma + mb = m(a + b) this is an algebra formule, what cyfers, NUMBERS STAND A and M for I suspect that slashes representing fractions are missing: m/a + m/b = mb + ma/ab = m(b + a)/ab
How do you change point-slope to slope-intercept?
Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.
How do you find the x intercept when you have slope and a point?
Obtain the coordinates of the point (a,b) Utilise the standard equation for a straight line y = mx + c The slope 'm' is known. Substituting a, b for x, y then b = ma + c : c = b - ma The equation now becomes y = mx + (b - ma) The x intercept occurs when y = 0 : substituting this gives :- 0 = mx + (b - ma) : mx = ma - b : x = (ma - b) ÷ m EXAMPLE : Slope is 5, Point coordinates are (2,4): x intercept = [(5 x 2) - 4] ÷ 5 = 6 ÷ 5 = 1.2
The sum of 38 and m?
Sum = 38 + M
How do you prove that the exterior angle of a triangle is equal to the sum of the two opposite interior angles?
Assume a triangle ABC with a line AB (containing the side AB) with external angle D which is formed when line AB and line segment AC intersect. We are asked to prove that the external angle D is equal to the sum of the two interior angles B and C. Angles A and D are supplementary angles (they sum to 180 degrees) because they are linear angles (both together make a straight line, or a 180 degree angle). This means: m<A + m<D = 180 degrees. m<A = 180 deg - m<D Then because A, B, and C are the three angles in a triange: m<A + m<B + m<C = 180 deg m<A = 180 deg - m<B - m<C By substituting 180 deg - m<D in for m<A in the above equation we get: 180 deg - m<D = 180 deg - m<B - m<C Subtract 180 deg from each side: -m<D = -m<B - m<C Multiply both sides by -1 m<D = m<B + m<C Which proves that the measure of the external angle D is equal to the sum of the two opposite interior angles B and C for any given triangle. wow. that's a lot. lol.
The sum of 3 times m and n?
the sum of 3 times m and n
How do you write a line in point-slope form?
The equation of a line passing through a point P with coordinates (a,b) and slope m is (y-b) = m(x-a) changing that to the more conventional form: y = mx + (b - ma)
How do you find the slope intercept form from 2 set of points?
Suppose the two points are (a,b) and (c,d) then the slope is (b-d)/(c-a). Write that as m. Then the equation of the line is y-b = m(x-a) which can be simplified to y = mx + b-ma
what id the sum of m and 6?
The sum of "m" and 6 is "m + 6".
What about nested for loop?
Possible. Example: void mat_mul (int m, int n, int l, const int **a, const int **b, int **c) { int i, j, k; double sum; for (i=0; i<m; ++i) { for (j=0; j<l; ++j) { sum= 0; for (k=0; k<n; ++k) { sum += a[i][k] * b[k][j]; } c[i][j]= sum; } }
Rearrange F equals ma?
F = MA M = F / A A = F / M
The sum of two numbers is 12. The sum of the squares of the same two numbers is 90. What are the two numbers?
We get a system of equations: a+b=12 a2+b2=90. Replace 12-a for b, and we get: a2+(12-a)2=90 2a2-24a+144=90 2a2-24a+54=0 a2-12a+27=0 a1=9 a2=3 Because of symmetry, we get two equivalent solutions: a=9, b=3 or a=3,b=9
