It is mA + mB
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ma + mb = m(a + b) this is an algebra formule, what cyfers, NUMBERS STAND A and M for I suspect that slashes representing fractions are missing: m/a + m/b = mb + ma/ab = m(b + a)/ab
Assume a triangle ABC with a line AB (containing the side AB) with external angle D which is formed when line AB and line segment AC intersect. We are asked to prove that the external angle D is equal to the sum of the two interior angles B and C. Angles A and D are supplementary angles (they sum to 180 degrees) because they are linear angles (both together make a straight line, or a 180 degree angle). This means: m<A + m<D = 180 degrees. m<A = 180 deg - m<D Then because A, B, and C are the three angles in a triange: m<A + m<B + m<C = 180 deg m<A = 180 deg - m<B - m<C By substituting 180 deg - m<D in for m<A in the above equation we get: 180 deg - m<D = 180 deg - m<B - m<C Subtract 180 deg from each side: -m<D = -m<B - m<C Multiply both sides by -1 m<D = m<B + m<C Which proves that the measure of the external angle D is equal to the sum of the two opposite interior angles B and C for any given triangle. wow. that's a lot. lol.
The equation of a line passing through a point P with coordinates (a,b) and slope m is (y-b) = m(x-a) changing that to the more conventional form: y = mx + (b - ma)
Suppose the two points are (a,b) and (c,d) then the slope is (b-d)/(c-a). Write that as m. Then the equation of the line is y-b = m(x-a) which can be simplified to y = mx + b-ma
(b+5)