A tree diagram for tossing 3 coins would start with a single point, representing the initial state. From this point, there would be two branches for the first coin, one for heads (H) and one for tails (T). Each of these branches would then split into two more branches for the second coin, resulting in HH, HT, TH, and TT. Finally, each of these outcomes would split again for the third coin, leading to a total of 8 possible outcomes: HHH, HHT, HTH, HTT, THH, THT, TTH, and TTT.
1/4 if they are tossed only once.
Since each coin would have the outcome with Heads and Tails: Then among the 32 coins, we can have the possible outcomes from no Heads, 1 Head, 2 Heads, ....... , 31 Heads, 32 Heads. Therefore we would have 33 outcomes.
If you know which coin is which, there are 16possible outcomes.If you're only counting the number of Heads and Tails, there are 5 .
7878
48
1/4 if they are tossed only once.
There are eight (8).
Since each coin would have the outcome with Heads and Tails: Then among the 32 coins, we can have the possible outcomes from no Heads, 1 Head, 2 Heads, ....... , 31 Heads, 32 Heads. Therefore we would have 33 outcomes.
1/2 x 1/2 x 1/2 = 1/8 or 0.125 also 12.5%
If you know which coin is which, there are 16possible outcomes.If you're only counting the number of Heads and Tails, there are 5 .
7878
48
There are two outcomes for each coin and three coins; 2 x 2 x 2 = 23 = 8 outcomes.
H and T blows
There are 72 permutations of two dice and one coin.
The number of combinations - not to be confused with the number of permutations - is 2*21 = 42.
We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).