Improved Answer:-If: 20x+27 = 143Then: x = 5.8
11x = 20x +1811x-20x=18x(11-20)=18-9x=18x=-2
20
20x + 5 - 20 = 21x + 4 -x = 4 + 15 x = -19
20x+7=5x+10 15x=3 3/15=.2 x=.2
If: y = x2+20x+100 and x2-20x+100 Then: x2+20x+100 = x2-20x+100 So: 40x = 0 => x = 0 When x = 0 then y = 100 Therefore point of intersection: (0, 100)
Improved Answer:-If: 20x+27 = 143Then: x = 5.8
11x = 20x +1811x-20x=18x(11-20)=18-9x=18x=-2
20x + 80y = 0Subtract 20x from each side of the equation:80y = -20xDivide each side by 80:y = -1/4 xm = -1/4b = 0
20
20x + 5 - 20 = 21x + 4 -x = 4 + 15 x = -19
20x+7=5x+10 15x=3 3/15=.2 x=.2
If: 20x+5y = 15 Then: y = -4x+3
The graphs of the two equations will intersect when x² + 20x + 100 = y = x² - 20x + 100 Subtracting x² +100 from both sides you get 20x = -20x that will only be true when x = 0. At x = 0, y = 100 for both equations - so the point of contact would be (0,100)
... You have to know what x and y are first.
x = -1.75
They touch each other at (0, 100) on the x and y axis.