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Assuming the missing operator before the final 5 is subtract, then: x2 - 4x - 5 = (x + 1) (x - 5) ⇒ x = -1 or 5. If it is add, there are no real root solution. The solution to the latter case is: x2 - 4x + 5 = (x - 2 - i)(x - 2 + i) ⇒ x = 2 + i or x = 2 - i.
x2 + 10x + 21 = (x + 3)(x + 7)
(x2+10x+21)/(x+3) = (x+7)
x2+10x+21 = (x+3)(x+7) when factored.....
It is: x2-10x+21 = 0 and the value of x is 3 or 7 when solved