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If you mean: y = x^2 -6x +6 then the vertex is at (3, -3)
No, but any parabola can be transformed into the form y = x^2.
Do you have a specific vertex fraction? vertex = -b/2a wuadratic = ax^ + bx + c
when the function is in vertex form: y = a(x - h)2 + k, the point (h, k) is the vertex.
They form a vertex.