18x2 + 9x + 13 can be expressed in the form, ax2 + bx + c, where a=18, b=9, and c=13.
The formula, x = -b/2a gives the x-coordinate of the vertex.
Therefore,
x = -9/2(18)
x = -9/36
x = -1/4
Substituting x=-1/4 into the orginal equation will give the y-coordinate of the vertex.
Therefore,
y = 18(-1/4)2 + 9(-1/4) + 13
y = 18(1/16) - 9/4 +13
y = 9/8 - 18/8 +13
y = 11 7/8
y = 95/8
Vertex = (-1/4 , 95/8)
(-3, -5)
= 18x + 13
4
(6x + 1)(x + 2)
If you mean: (x+3)^2 = (x+2)^2 +13 Then the value of the number x works out as 4
(-3, -5)
= 18x + 13
2^2 + 3^2 = 4 + 9 = 13
X2 + 10X - 13 = 17 add 13 to each side X2 + 10X = 30 halve the linear coefficient ( 10 ), square it and add it to both sides X2 + 10X + 25 = 30 + 25 factor on the left and gather terms on the right (X + 5)2 = 55 (X + 5)2 - 55 = 0 ---------------------------vertex form, (- 5, - 55 ), is the vertex -------------------------------------------[-------------------------------]
81. To complete the square, halve the coefficient of the x term (18/2 = 9) and add the square of this (92 = 81) to both sides: x2 + 18x = -13 ⇒ x2 + 18x + 81 = -13 + 81 ⇒ (x + 9)2 = 68
4
4
(6x + 1)(x + 13)
This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.
(6x + 1)(x + 2)
[(x+3)^2] - [(x+2)^2] = 13 ==> 2x = 8 ==> x = 4. the number is 4!
If you mean: (x+3)^2 = (x+2)^2 +13 Then the value of the number x works out as 4