The vertex of x2 - 5x + 6 is (2.5, -.25).
(This can be solved with calculus:
Take the derivative of x2 - 5x + 6, which is 2x- 5.
Then set it equal to zero to get the x value: 2x - 5 = 0, so x = 2.5. Plug this value back into x2 - 5x + 6 to get the y value: -.25. In pre-calculus, this is normally done by using a graphing calculator instead.)
The vertex can be found by using the formula x = -b / (2a), where a is the coefficient of x^2 and b is the coefficient of x. In this case, a = 1 and b = -5, so the vertex is x = -(-5) / (2*1) = 5/2. Plugging this value of x back into the equation gives us y = (5/2)^2 - 5(5/2) + 6 = 1/4. Therefore, the vertex is (5/2, 1/4).
(3, -21)
The vertex is (-9, -62).
The vertex is at (-1,0).
y=aX2+bX+c ---> y=X2-6X+5vertex formula is -b/2a( b=-6,a=1)vertex=-(-6)/2*1=6/2=3 y=32-6(3)+5---->y=-4so vertex is (3,4)
The vertex has a minimum value of (-4, -11)
1.6667
(3, -21)
The vertex is (-9, -62).
The vertex is at (-1,0).
y=aX2+bX+c ---> y=X2-6X+5vertex formula is -b/2a( b=-6,a=1)vertex=-(-6)/2*1=6/2=3 y=32-6(3)+5---->y=-4so vertex is (3,4)
The vertex has a minimum value of (-4, -11)
It is the average of -2 and +6, that is, x = 2
2x2 + 4 + 1 = 2x2 + 5 So, the vertex is (0, 5)
A vertex of a 3-d object, such as a star, where 6 faces meet.
The equation is linear and so has no vertex.
(-4,-1)
The vertex is at the point (0, 4).